Geometry Proofs

Geometry Proofs

10th Grade

16 Qs

quiz-placeholder

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Geometry Proofs

Geometry Proofs

Assessment

Quiz

Mathematics

10th Grade

Medium

CCSS
HSG.CO.C.9, HSG.CO.B.8, HSG.CO.D.12

+5

Standards-aligned

Created by

Mark Siroonian

Used 1K+ times

FREE Resource

16 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

Given: 1 and 3 are vertical angles. What should you conclude by the vertical angles theorem?

 1\angle1  and 3\angle3  are a linear pair

 \angle1  and \angle3  are right angles.

 23\angle2\cong\angle3  

 13\angle1\cong\angle3  

Tags

CCSS.HSG.CO.C.9

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Given: ∠1 and ∠2 are supplementary. What can you conclude?

m1+m2=180°m\angle1+m\angle2=180\degree

m1+m2=90°m\angle1+m\angle2=90\degree

m1=m2m\angle1=m\angle2

Nothing

Tags

CCSS.HSG.CO.C.9

3.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Media Image

What does it mean to bisect a segment or an angle?

Split it into 3 equal parts.

Split it into 2 equal parts.

Split into 4 equal parts.

Double it.

Tags

CCSS.HSG.CO.D.12

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

In the given proof, what are the reasons for step 1 and 2?

Angles that form a linear pair are supplementary.

Substitution

Reflexive Property of Congruence

Angles of equal measure are congruent.

Tags

CCSS.HSG.CO.C.9

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

In the given proof, what is the reason for step 1?

Angles that form a linear pair are supplementary.

Angles of Equal Measure are Congruent

Reflexive Property of Congruence

Definition of a Perpendicular Bisector

Tags

CCSS.HSG.CO.C.9

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

In the given proof, what is the statement for step 2?

Angles that form a linear pair are supplementary. m1+m3=180°m∠1+m∠3=180°  

 m3+m5=180°m∠3+m∠5=180°  

 m1=m3m∠1=m∠3  

 35\angle3\cong\angle5  

Tags

CCSS.HSG.CO.C.9

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

In the given proof, what is the statement for step 2?

 ADDBAD≅DB  

 CDCDCD≅CD  

 mADC+mBDC=180°m\angle ADC+m\angle BDC=180\degree  

 ADCBDC\angle ADC\cong\angle BDC  

Tags

CCSS.HSG.CO.B.6

CCSS.HSG.CO.B.7

CCSS.HSG.CO.B.8

CCSS.HSG.CO.C.10

CCSS.HSG.SRT.B.4

CCSS.HSG.SRT.B.5

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