
Systems of Equations - Recap
Authored by J Deming
Mathematics
8th - 9th Grade
CCSS covered
Used 746+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
What is the first step?
y = x + 8
x + y = 2
substitute x + 8 for y in the second equation
substitute x + 8 for x in the second equation
substitute x + y for y in the first equation
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
2.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is first step?
x = 3y
2x + 4y = 10
2x + 4(3y) = 10
2(3y) + 4y = 10
x = 3(2x + 4y)
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
3.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step?
y = -2x - 2
5x + 3y = -8
Step 1: 5x + 3(-2x - 2) = 8
Step 2: ?
Distribute the 3
Subtract the 5x
Add 8 to both sides
Add 5x to both sides
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
4.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step?
5x + 2y = 7
y = -4x + 8
Step 1: 5x + 2(-4x + 8) = 7
Step 2: 5x - 8x + 16 = 7
Step 3: -3x + 16 = 7
Step 4:
add 3x to each side
subtract 7 from each side
subtract 16 from each side
add 16 to each side
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
5.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step?
2x - 3y = -12
y = -x + 9
Step 1: 2x - 3(-x + 9) = -12
Step 2: 2x + 3x - 27 = -12
Step 3: 5x - 27 = -12
Step 4: 5x = 15
Step 5: x = 3
Step 6: ?
substitute 3 for x in y = -x + 9
substitute 3 for x in 2x - 3y = -12
either option will work
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
6.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the first step?
2x - 3y = 14
x + 3y = -11
solve each equation for y
add the equations to eliminate the y's
subtract the equations to eliminate the y's
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
7.
MULTIPLE CHOICE QUESTION
30 sec • 1 pt
What is the next step?
-3x - 4y = -1
3x - y = -4
Step 1: -5y = -5
Step 2: ?
add 5 to both sides
subtract 5 from both sides
multiply -5 to both sides
divide both sides by -5
Tags
CCSS.8.EE.C.8B
CCSS.HSA.REI.C.6
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