Systems of Equations - Recap

substitute x + 8 for y in the second equation

substitute x + 8 for x in the second equation

substitute x + y for y in the first equation

2x + 4(3y) = 10

2(3y) + 4y = 10

x = 3(2x + 4y)

Distribute the 3

Subtract the 5x

Add 8 to both sides

Add 5x to both sides

add 3x to each side

subtract 7 from each side

subtract 16 from each side

add 16 to each side

substitute 3 for x in y = -x + 9

substitute 3 for x in 2x - 3y = -12

either option will work

solve each equation for y

add the equations to eliminate the y's

subtract the equations to eliminate the y's

add 5 to both sides

subtract 5 from both sides

multiply -5 to both sides

divide both sides by -5

substitute -2 in for x in either equation

substitute -2 in for y in either equation

Nothing. The problem is solved.

divide both sides by -4

add 20 to both sides

subtract 20 from both sides

add 4 to both sides

multiply either equation by -1

(to create opposites and eliminate the x's)

multiply the bottom equation by 2

(to create opposites and eliminate the y's)

subtract the equations (top-bottom)

(to eliminate the x's)

all options would work