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Applications of Quadratic Equations

Authored by Danielle Freeman

Mathematics

9th - 12th Grade

Used 28+ times

Applications of Quadratic Equations
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10 questions

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1.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

The function f(t) = -5t2 + 20t + 60 models the approximate height of an object t seconds after it is launched. How many seconds does it take the object to hit the ground?

4 seconds

-2 seconds

6 seconds

9 seconds

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Rafael kicks a ball in the air. This equation represents the approximate height, in meters, of the ball above the ground after t seconds.

h(t) = -5t2 + 45t


How long is the ball in the air?

0 seconds

3 seconds

9 seconds

45 seconds

3.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

A diver is standing on a platform above the pool. He jumps from the platform with an initial upward velocity of 8 ft/s.

h(t) = −16t2 + 8t + 24

The function h(t) represents his height above the water in feet after t seconds.


What was the initial height of the diver?

0.25 ft

24 ft

25 ft

8 ft

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The path of an arrow is represented by the function, where h(t) is the height of the arrow (in feet) after t seconds.

h(t) = -16t2 +20t + 6


When will the arrow hit the ground?

6 seconds

20 seconds

-0.25 seconds

1.5 seconds

5.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

A lizard is jumping across the water in search of food. The function below models the lizard's height (in feet) above the water t seconds after he jumps.

h(t) = -12t2 + 6t


How long after jumping is he back on the water?

12 seconds

0.25 seconds

0.50 seconds

6 seconds

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

If a toy rocket is launched vertically upward from ground level with an initial velocity of 128 feet per second, then its height h after t seconds is given by the equation

h(t) = -16t2 +128t

What is the maximum height of the rocket?

4 feet

0 feet

128 feet

256 feet

7.

MULTIPLE CHOICE QUESTION

15 mins • 1 pt

The profit from selling local ballet tickets depends on the ticket price. Using past receipts, we find that the profit can be modeled by the function below, where x is the price of each ticket.

p(x)= -15x2 +600x +60


What is the maximum profit you can make from selling tickets?

$6060

$20

$600

$10,250

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