Unit 4 Days 1-4 Review

Find the distance between (-5, -8) and (-1, -16).

• 8.9
• 9.8
• 10.3
• 11

Tags

CCSS.HSG.GPE.B.7

Find the distance.

• 9.7
• 10.7
• 11.7
• 12.7

Tags

CCSS.HSG.GPE.B.7

What is the midpoint between (3, -1) and (7, -5)

• (5, -2)
• (10, -6)
• (5, -3)
• (2, -2)

Tags

CCSS.HSG.GPE.B.6

What is the midpoint between (-4,4) and (-2,2)?

• (3,2)
• (-3,3)
• (4,5)
• (6,7)

Tags

CCSS.HSG.GPE.B.6

If you are given the diameter, how can you calculate the radius?

• Multiply the diameter by 2
• Divide the diameter by 2
• Add 2 to the diameter
• Subtract 2 from the diameter

Tags

CCSS.7.G.B.4

The definition of radius is

• distance from one point to another point

• distance around the circle

• distance from the center to any point on the circle

• distance across the circle through the center

Tags

CCSS.HSG.C.A.2

In the equation (x-3)²+(y-2)²=16, the center of the circle is...

• (3,2)
• (-3, -2)
• (-2, -3)
• (2, 3)

Tags

CCSS.HSG.GPE.A.1

In the equation (x+2)²+(y-3)²=4, the radius of the circle is...

• 4
• 2
• 3
• 16

Tags

CCSS.HSG.GPE.A.1

Write the standard equation of the circle with the given center and radius; center (0,0) and radius: 3

• x²+y²=3
• x²+y²=6
• x²+y²=9

Tags

CCSS.HSG.GPE.A.1

The diameter of a circle has length 12. The center is at (-5, 2). Give the equation of the circle.

• (x - 2)² + (y + 5)² = 36
• (x - 5)² + (y + 2)² = 6
• (x + 5)² + (y - 2)² = 36
• (x + 2)² + (y - 5)² = 6

Tags

CCSS.HSG.GPE.A.1