GCSE Revision Quiz

GCSE Revision Quiz

7th - 12th Grade

10 Qs

quiz-placeholder

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GCSE Revision Quiz

GCSE Revision Quiz

Assessment

Quiz

Mathematics

7th - 12th Grade

Medium

long multiplication, ratio, percentages, percentage increase

+2

Standards-aligned

Created by

Sarah Matthews

Used 14+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

23 × 17

391

390

392

381

Answer explanation

This is long multiplication. Remember, put the larger number on top and start multiplying with the ones!

Tags

long multiplication

2.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Share £48 in the ratio 3: 5

£12 : £36

£18 : £30

£9 : £39

£18 : £35

Answer explanation

In order to solve this, you need to work out what the individual parts of the ratio are worth. Do this by adding them together:

3+5 = 8

Then, divide the total amount, by the total parts

48 ÷\div 8 = 6


So each individual part is worth £6.

Lastly, multiply each side of the ratio by 6, in order to find the missing values:


6 ×\times 3 = 18

6 ×\times 5 = 30

So the final answer is:

£18 : £30

Tags

ratio

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Increase 120 by 10%

134

126

130

132

Answer explanation

This topic is percentage increase. The best way to do it is to create a decimal multiplier:

120 = 100%

You want to find 10% on top of that:

100% + 10% = 110%

Turn your 110% into a decimal:

110100= 1.1\frac{110}{100}=\ 1.1


Multiply your original amount by the decimal to find the answer:

1.1 ×120 = 1321.1\ \times120\ =\ 132
The alternative method is to find 10% by dividing your original number by 10, then adding it onto the original amount: 12010 =12 \frac{120}{10}\ =12\ \ 120 +12 =132120\ +12\ =132

Its better if you can use the decimal method though, as it will allow you to deal with more complex questions involving percentages, especially compound interest.

Tags

percentages, percentage increase

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Round 324 to 1sf

320

324.0

300

325

Answer explanation

You will be asked to round a number to a certain number of 'sf' or significant figures. This is an alternative to rounding to a certain number of dp.


To do this, you must count from the first number higher than 0 (so 0.0123 would be counted from the 1). Count along until you have the required number of significant figures, then use the rules of rounding to complete your answer. Complete the number with zeros.


In the question, the first significant figure is 3. The number is 324, so we need to maintain its size with zeros as place holders . Using the rules of rounding, we round down to 300.

Tags

significant figures, rounding

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Estimate 19 × 47=

1000

893

890

950

Answer explanation

When you are estimating, you are rounding the numbers to the nearest, easy to calculate figures. In this case, that's 20 and 50.

20 ×\times 50 = 1000
Watch out for the word 'estimate' in questions!

6.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Expand 2(𝑥 + 3)

2𝑥 + 3

2𝑥 + 5

2𝑥 + 9

2𝑥 + 6

Answer explanation

This topic is expanding. When expanding brackets, you must multiply everything outside the bracket with everything inside it.

Tip: Remember 2x2x means 2 × x2\ \times\ x you don't need to write the ×\times sign

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Solve 3𝑥 + 2 = 11

x = 3x\ =\ 3

x = 6x\ =\ 6

x = 4x\ =\ 4

x = 10x\ =\ 10

Answer explanation

This topic is solving an equation. Remember to write out all the steps when answering questions like this:

3x + 2 = 113x\ +\ 2\ =\ 11

You need to get xx on its own. Begin by cancelling out the +2+2 by subtracting 22 . This must be done on both sides of the equal sign.

3x = 93x\ =\ 9

Now, you need to get down to xx . You can remove the ×3\times3 by doing the opposite, ÷3\div3 (again, on both sides)
3x3=93\frac{\text{3}x}{\text{3}}=\frac{9}{3} x =3x\ =3

Tags

solving, algebra

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