Derivatives

Derivatives

10th - 12th Grade

10 Qs

quiz-placeholder

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Derivatives

Derivatives

Assessment

Quiz

Mathematics, English

10th - 12th Grade

Medium

Created by

Đức Phạm

Used 44+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

10 sec • 1 pt

The first derivative of function y=3xy=3x is

 y=3xy'=3x  

 y=3y'=3  

 y=xy'=x  

 y=x3y'=x^3  

2.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which of the following formula is true?

(uv)=uv+uv\left(u\cdot v\right)'=u'\cdot v+u\cdot v'

(uv)=uv\left(u\cdot v\right)'=u'\cdot v'

(uv)=uv+uv\left(u\cdot v\right)'=u'\cdot v'\cdot+u\cdot v

(uv)=u+v\left(u\cdot v\right)'=u'+v'

3.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

Which of the following formula is true?

(uv)=uv+uvu2 (u0)\left(\frac{u}{v}\right)'=\frac{u'\cdot v+u\cdot v'}{u^2}\ \left(u\ne0\right)

(uv)=uvuvu2 (u0)\left(\frac{u}{v}\right)'=\frac{u'\cdot v-u\cdot v'}{u^2}\ \left(u\ne0\right)

(uv)=uv+uvv2 (v0)\left(\frac{u}{v}\right)'=\frac{u'\cdot v+u\cdot v'}{v^2}\ \left(v\ne0\right)

(uv)=uvuvv2 (v0)\left(\frac{u}{v}\right)'=\frac{u'\cdot v-u\cdot v'}{v^2}\ \left(v\ne0\right)

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the derivative of function y=x+13x2y=\frac{x+1}{3x-2} 


 y=5(3x2)2y'=\frac{5}{\left(3x-2\right)^2}  

 y=5(3x2)2y'=\frac{-5}{\left(3x-2\right)^2}  

 y=1(3x2)2y'=\frac{-1}{\left(3x-2\right)^2}  

 y=1(3x2)2y'=\frac{1}{\left(3x-2\right)^2}  

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Find the derivative of function y=12xx+2y=\frac{1-2x}{x+2} 


 y=4(x+2)2y'=\frac{4}{\left(x+2\right)^2}  

 y=3(x+2)2y'=\frac{3}{\left(x+2\right)^2}  

 y=5(x+2)2y'=\frac{-5}{\left(x+2\right)^2}  

 y=1(x+2)2y'=\frac{-1}{\left(x+2\right)^2}  

6.

MULTIPLE CHOICE QUESTION

20 sec • 1 pt

The derivative of function y=xny=x^n  is


 y=x(n1)y'=x^{\left(n-1\right)}  

 y=(n1)xny'=\left(n-1\right)x^n  

 y=nx(n1)y'=n\cdot x^{\left(n-1\right)}  

 y=(n1)x(n1)y'=\left(n-1\right)x^{\left(n-1\right)}  

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The derivative of function y=2xy=\sqrt{2x}  is


 y=12xy'=\frac{1}{\sqrt{2x}}  

 y=12xy'=\frac{1}{2\sqrt{x}}  

 y=122xy'=\frac{1}{2\sqrt{2x}}  

 y=22xy'=\frac{2}{\sqrt{2x}}  

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