Integration by Parts

What is the Integration by Parts Formula?

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What would you choose for your u here if you used integration by parts?

• t

• 3t

• e^2t

• e^t

• don't use IBP, let u = 2t

Tags

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.B.3

CCSS.HSF.BF.A.1

Evaluate the indefinite integral using integration by parts. 
 $\int3x\ e^{2x}\ dx\$  

•  $-\frac{xe^{2x}}{2}+\frac{e^{2x}}{4}+C$  

•  $\frac{3xe^{2x}}{2}-\frac{3e^{2x}}{4}+C$  

•  $xe^{-2x}+\frac{\left(1-x^2\right)^{ }}{2}+C$  

•  $-\frac{xe^{2x}}{2}+\frac{\ln e^{2x}}{4}+C$  

Evaluate the indefinite integral using integration by parts. 
 $\int t^2\ln t\ dt\$  

•  $\frac{2t^2\ln2t-t^2}{4}+C$  

•  $\frac{t^3\ \ln3}{3}-\frac{t^3}{9}+C$  

•  $\frac{e^t}{2t+2}+C$  

•  $\frac{-2t-1}{4e^{2t}}+C$  

Tags

CCSS.HSF.BF.B.5

 $\int_{ }xe^x\ dx$  by using integration by parts.

•  $xe^x-\ e^x+c$  

•  $xe^x+e^x+c$  

•  $xe^x+c$  

•  $xe^x-e^x$  

Evaluate the indefinite integral using integration by parts. u and v ' are provided.
 $\int t\sin t\ dt\ ;\ \ \ u=t,\ v\ '=\sin t\$  

•  $t\cos^{-1}t-\left(1-t^2\right)^{\frac{1}{2}}+C$  

•  $-t\cos t+\sin t+C$  

•  $t\sin^{-1}t+\left(1-t^2\right)^{\frac{1}{2}}+C$  

•  $t\sin t+\cos t+C$  

What would you choose for your u here if you used integration by parts?

• x

• sin(x)

• cos(x)

• e^x

What would you choose for your u here if you used integration by parts?

• x
• x⁴
• e^-x
• e^x

Tags

CCSS.HSA.SSE.A.1

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3