Rational Functions Part 2 Test

What is the vertical asymptote?

 $f\left(x\right)=\frac{2x+2}{x-5}$  

• x=5

• x=0

• x=-5

• x=2

What is the horizontal asymptote?

 $f\left(x\right)=\frac{2x-4}{3x+2}$  

•  $y=\frac{2}{3}$  

•  $y=\frac{-4}{2}$  

•  $y=\frac{3}{2}$  

•  $y=-2$  

Select ALL the information that applies to the given rational function. $f\left(x\right)=\frac{2x^2-2}{x^2-4x+3}$  

• Vertical Asymptote. at x = -3 and x = 1

• Hole at (1, 0)

• Horizontal Asymptote at y = 2

• x-intercepts at (3,0) and (1, 0)

The horizontal asymptote equals zero when:

• the degree of the numerator and denominator are equal

• the degree of the numerator is less than the degree of the denominator

• the degree of the numerator is greater than the degree of the denominator

• the numerator equals zero

 Graph the function.

 $f\left(x\right)=\frac{-2x^2+2x+24}{x^3-x^2-12x}$ 

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 $f\left(x\right)=\frac{2x^2+x+1}{x+1}$  Graph the function.

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Solve for x:  $\frac{5}{3}-\frac{2}{x}=\frac{8}{x}$  

•  $2$  

•  $\frac{18}{5}$  

•  $\frac{26}{5}$  

•  $6$  

Solve:  $\frac{3}{x-5}-\frac{20}{x^2-25}=\frac{2}{x+5}$  

•  $x=-5$  

•  $x=5$  

•  $\frac{5}{\left(x+5\right)\left(x-5\right)}$  

• No Solution

Solve for x:  $\frac{5}{x+2}=\frac{1}{x-4}$  

• x = 5

• x = 4

• x = 5.5

• x = -4

Solve 

• x = 0 , 4
• x = 1 , 3
• x = -4 , 0
• x = 5 , 2