A particle moves along a straight line and passes through a fixed point O. Its displacement, s m, is given by s = 2t² – 5t – 3, where t is the time in seconds after the movement begins. Find the instantaneous displacement, in m, of the particle when t = 0
ADDMATH CHAPTER 8

Quiz
•
Mathematics
•
1st - 10th Grade
•
Hard
mrsm mersing
Used 13+ times
FREE Resource
20 questions
Show all answers
1.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
-2
0
-3
3
2.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A particle moves along a straight line and passes through a fixed point O. Its velocity, v ms–1, is given by v = t² – 8t + 7, where t is the time in seconds after passing through O. Find the instantaneous velocity, in ms–1, of the particle when t = 3.
-8
5
7
-9
3.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A particle moves along a straight line and passes through a fixed point O. Its acceleration,
a ms–2, is given by a = 8 – 4t, where t is the time in seconds after passing through O. Find the instantaneous acceleration, in ms–2, of the particle when t = 4.
-4
2
-7
-8
4.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A particle moves along a straight line from a fixed point O. Its displacement, s m, t seconds after passing through O is given by s = 4t² + t. Calculate the total distance, in m, travelled by the particle when 0 < t < 4
66
67
68
69
5.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
A particle moves along a straight line and passes through a fixed point O. Its displacement, s m, t seconds after it starts moving is given by s = 6t – t² + 7. The particle moves to the right of O until t = 3 and then moves towards O again. Find the total distance, in m, travelled by the particle in the first 2 seconds
7
8
5
4
6.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Determine the velocity function, v in terms of t for a particle that moves along a straight line in s = t(2 – t)²
v = 4 - 8t + 3t²
v = 8 + 4t - 3t²
v = 4 - 4t - 6t²
v = 8 + 8t + 6t²
7.
MULTIPLE CHOICE QUESTION
2 mins • 1 pt
Determine the velocity function, v in terms of t for a particle that moves along a straight
line in s = 2t³ – 4t² + 2t + 1
v = 3t² - 8t +6
v = 6t² - 4t +2
v = 3t² - 4t +6
v = 6t² - 8t +2
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