Kwadraten 1 gr9

 $\sqrt{25}=$  

 $\sqrt{121}=$  

 $4+\left(5+3\right)-2\times6\div4$  

stel a = 5 en b = 2 in 3ab =

 $\sqrt{-36}\ =$  

in a^b is a het ....

in a^b is b de ....

-4² =

(-12)² =

 $-\sqrt{169}=$