DIFFERENTIAL EQUATIONS

Given the differential equation dP/Dt=5P

Find the general solution for P to the differential equation.

(the next question will use this answer)

• P=e^5t

• P=Ce^5t

• P=e^5t+C

• P=Ce^t

Given the differential equation dP/Dt=5P

Find the particular solution for P to the differential equation given P(0)= 418

• P= 5e^418t

• P= 418e^t

• P= 418e^5t

• P= 418e^10t

dy/dx = 2x/e^2y find the general solution

• y = ln (2x/2 + C)

  2

• y = ln(2x/2)+c

• y = e^2x+c

• y = mx+b

2. Solve the differential equation

𝑑𝑦/𝑑𝑡 =3𝑡²/𝑦 with initial condition

𝑦(2) = 0.

• 𝑦 = ln(15t)

• 𝑦 = 16t³

• 𝑦 = (2𝑡³ − 16)^1/2

• 𝑦 = (2𝑡³ −16)

Find the particular solution for y if dy/dx = 2x√y and y = 4 when x = 3.

• 2√y = x² + C

• y = (x² + 25)²/4

• y = (x²/2-5/2)^1/2

• y = x⁴/4

Tags

CCSS.HSA-REI.B.4B