quadratic formula

Determine the values of a, b, and c for the quadratic equation:

4x² – 8x = 3

• a = 4, b = -8, c = 3

• a = 4, b =-8, c =-3

• a = 4, b = 8, c = 3

• a = 4, b = 8, c = -3

What is this formula?

• This is the standard formula.

• This is the quadratic formula.

• This is the square root formula.

• This is the Pythagorean formula

Identify the 'b' value: y = 16x² -8x -24

• 16
• -8
• 8
• -24

In the equation
y = x² +5x +7, match each leading coefficient with its correct letter 

• a=0, b=5, c=7
• a=1, b=5, c=7
• a=7, b=5, c=1

Identify the 'c' value: y = 16x² -8x -24

• 16
• -8
• 24
• -24

For the equation  $5x^2-3x-2=0$  , plugging in your values for a, b, and c into the quadratic formula would look like:

•  $x=\frac{-3\pm\sqrt{-3^2-4\left(5\right)\left(-2\right)}}{2\left(5\right)}$  

•  $x=\frac{-3\pm\sqrt{\left(-3\right)^2-4\left(5\right)\left(-2\right)}}{2\left(5\right)}$  

•  $x=\frac{3\pm\sqrt{-3^2-4\left(5\right)\left(-2\right)}}{2\left(5\right)}$  

•  $x=\frac{3\pm\sqrt{\left(-3\right)^2-4\left(5\right)\left(-2\right)}}{2\left(5\right)}$  

The simplified version of  $x=\frac{3\pm\sqrt{\left(-3\right)^2-4\left(5\right)\left(-2\right)}}{2\left(5\right)}$  is:

•  $x=\frac{3\pm\sqrt{-9-40}}{10}$  

•  $x=\frac{3\pm\sqrt{-9+40}}{10}$  

•  $x=\frac{3\pm\sqrt{9-40}}{10}$  

•  $x=\frac{3\pm\sqrt{9+40}}{10}$  

For the equation  $4x^2-20x+25=0$  , plugging in your values for a, b, and c into the quadratic formula would look like:

•  $x=\frac{-20\pm\sqrt{-20^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{-20\pm\sqrt{\left(-20\right)^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{20\pm\sqrt{\left(-20\right)^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{20\pm\sqrt{-20^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

The simplified version of  $x=\frac{20\pm\sqrt{\left(-20\right)^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  is:

•  $x=\frac{20\pm\sqrt{-400-400}}{8}$  

•  $x=\frac{20\pm\sqrt{400-400}}{8}$  

•  $x=\frac{20\pm\sqrt{-40-400}}{8}$  

•  $x=\frac{20\pm\sqrt{40-400}}{8}$  

For the equation  $4x^2-20x+25=0$  , plugging in your values for a, b, and c into the quadratic formula would look like:

•  $x=\frac{-20\pm\sqrt{-20^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{-20\pm\sqrt{\left(-20\right)^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{20\pm\sqrt{\left(-20\right)^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$  

•  $x=\frac{20\pm\sqrt{-20^2-4\left(4\right)\left(25\right)}}{2\left(4\right)}$