In graph i, acceleration is ( + / - / 0 ) and the object is ____.

+ / moving with constant acceleration

- / moving with constant acceleration

+ / moving with increasing acceleration

- / moving with decreasing acceleration

In graph ii, acceleration is ( + / - / 0 ) and the object is ____.

- / moving with constant acceleration

+ / moving with constant acceleration

- / moving with increasing acceleration

In graph iii, acceleration is ( + / - / 0) and the object is ____.

0 / moving with constant velocity

+ / moving with increasing acceleration

- / moving with constant acceleration

+ / moving with constant acceleration

In graph 1, velocity is ( + / - / 0 ) and the object is ____.

+ / moving with constant velocity.

- / moving with constant velocity.

+ / moving with increasing velocity.

In graph 2, velocity is ( + / - / 0 ) and the object is ____.

+ / moving with increasing velocity.

+ / moving with constant velocity.

- / moving with constant velocity.

- / moving with increasing velocity

In graph 3, velocity is ( + / - / 0 ) and the object is ____.

- / moving with constant velocity.

+ / moving with constant velocity.

- / moving with increasing velocity

+ / moving with increasing velocity.

In graph 4, velocity is ( + / - / 0 ) and the object is ____.

- / moving with increasing velocity

+ / moving with constant velocity.

- / moving with constant velocity.

+ / moving with increasing velocity.

What is this object doing?

Moving to the right; speeding up.

Moving to the right; slowing down to a rest.

Moving to the left; slowing down to a rest.

Moving to the right; moves with a constant speed.

What is this object doing?

Moving to the left; speeding up.

Moving to the right; speeding up.

Moving to the left; slowing down to a stop.

Moving to the right; slowing down and stops.

What is this object doing?

Speeds up to the right; slows down to change direction; speeds up to the left to where it started.

Moving to the right; speeds up to change direction to the left; moves to the left; slows down to where it started.

Moving to the left; slows down to change direction to the right; moves to the right; speeds up to where it started.

Moving to the right; slows down to change direction to the left; moves to the left; slows down to where it started.

What is this object doing?

Moving up, slows to a rest; then moves down; speeding up.

Moving up, speeds up; then moves down; speeding up.

Moving up, slows to a rest; then moves down; slowing down.

Moving up at a constant speed; then moves down with a constant speed.

What is this object doing?

Moving to the right, slows to a rest to change direction, moves to the left; speeding up.

Moving to the right, speeds up and changes direction; moves to the left; speeding up.

Moving to the right, speeds up and changes direction; moves to the left; slowing down.

Moving to the right, moves with a constant speed; changes direction and moves to the left with a constant speed.

What is this object doing?

Moving to the left with a constant speed.

Moving to the left with increasing speed.

Moving to the left with decreasing speed.

Moving to the right with a constant speed.

What is this object doing?

Speeding up to the left or downward with a constant acceleration.

Speeding up to the right or upward with a constant acceleration.

Slowing up to the left or downward with a constant acceleration.

Slowing up to the right or upward with a constant acceleration.

AP PHYSICS 1 - MOTION GRAPHS

Authored by Ernest Kelly

Physics

10th - 12th Grade

NGSS covered

Used 300+ times

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25 questions

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MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is object doing at t = 4 s to t = 6 s?

At rest

Speeding up

Slowing down

What is object doing at t = 7 s to t = 9 s?

moving backward.

speeding up

moving forward

slowing down

MULTIPLE CHOICE QUESTION

1 min • 1 pt

At what time interval does the object have the greatest speed?

t = 6 s to t = 9 s

t = 1 s to t = 4 s

t = 4 s to t = 6 s

MULTIPLE CHOICE QUESTION

1 min • 1 pt

What is the object doing between t = 5 s and t = 10 s?

moving backward

speeding up

slowing down

moving forward

What is the velocity of the object between t = 0 and t = 5 s?

0.8 m/s

0.6 m/s

0.5 m/s

0.9 m/s

Answer explanation

velocity = slope = Δx/Δt.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

What is the distance the object moved from t = 0 min. to t = 10 min.?

300 m

30 m

6 m

600 m

Answer explanation

distance/displacement = area under curve.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

From t = 15 min. to t = 30 min., the object is (slowing down / speeding up) because its velocity is (+ / -) and its acceleration is (+ / -).

slowing down , +v , -a

speeding up , +v , -a

slowing down , -v , -a

slowing down , -v , +a

Answer explanation

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

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AP PHYSICS 1 - MOTION GRAPHS

What is object doing at t = 4 s to t = 6 s?

What is object doing at t = 7 s to t = 9 s?

At what time interval does the object have the greatest speed?

What is the object doing between t = 5 s and t = 10 s?

What is the velocity of the object between t = 0 and t = 5 s?

velocity = slope = Δx/Δt.

What is the distance the object moved from t = 0 min. to t = 10 min.?

distance/displacement = area under curve.

From t = 15 min. to t = 30 min., the object is (slowing down / speeding up) because its velocity is (+ / -) and its acceleration is (+ / -).

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

From t = 30 min. to t = 40 min., the object is (slowing down / speeding up) because its velocity is (+ / -) and its acceleration is (+ / -).

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

At which time interval is the acceleration = 0?

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

What is the acceleration of the object from t = 15 s to t = 40 s?

a = Δv/Δt

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AP PHYSICS 1 - MOTION GRAPHS

What is object doing at t = 4 s to t = 6 s?

What is object doing at t = 7 s to t = 9 s?

At what time interval does the object have the greatest speed?

What is the object doing between t = 5 s and t = 10 s?

What is the velocity of the object between t = 0 and t = 5 s?

velocity = slope = Δx/Δt.

What is the distance the object moved from t = 0 min. to t = 10 min.?

distance/displacement = area under curve.

From t = 15 min. to t = 30 min., the object is (slowing down / speeding up) because its velocity is (+ / -) and its acceleration is (+ / -).

objects speed up when v and a have the same sign;they slow down when they have opposite signs.objects are at rest or moving with a constant v when a = 0.

From t = 30 min. to t = 40 min., the object is (slowing down / speeding up) because its velocity is (+ / -) and its acceleration is (+ / -).

objects speed up when v and a have the same sign;they slow down when they have opposite signs.objects are at rest or moving with a constant v when a = 0.

At which time interval is the acceleration = 0?

objects speed up when v and a have the same sign;they slow down when they have opposite signs.objects are at rest or moving with a constant v when a = 0.

What is the acceleration of the object from t = 15 s to t = 40 s?

a = Δv/Δt

Access all questions and much more by creating a free account

Similar Resources on Wayground

Popular Resources on Wayground

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objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.

objects speed up when v and a have the same sign;
they slow down when they have opposite signs.
objects are at rest or moving with a constant v when a = 0.