Solving Quadratics by Factoring

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Solve:

k² - 2k - 24 = 0

• k = -4, 6

• k = -4, -6

• k = -6, 1

• k = 4, -6

Solve:

3x² + 18x +15 = 0

Hint: Factor GCF first.

• x = 3, 2

• x = 5, 1

• x = -5, -1

• x = -3, -2

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Solve
x² + 7x + 12 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Solve
x² + 13x + 12 = 0

• x = -1, x = -12
• x = -1, x = -24
• x = -2, x = -6
• x = -2, x = -12

Solve by factoring: x² - 9x + 20 = 0

• x = -4 and x = -5
• x = 20 and x = -9
• x = 4 and x = 5
• x = -4 and x = 5

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2