PC Exponential and Log Mid Unit Review

Logarithmic functions are the inverse of...

• Linear Functions
• Exponential Functions 
• Quadratic Functions 
• Polynomial Functions 

 Condense: $\log16+\log2\ -\log8$  

•  $\log4$  

•  $\log8$  

•  $\log10$  

•  $\log24$  
  

To solve, 16^5x = 64^x+7, what would be the correct set-up?

There is more than one correct answer.

• 4^4(5x)=4^16(x+7)

• 8^2(5x)=8^8(x+7)

• 4^2(5x)=4^3(x+7)

• 2^4(5x)=2^6(x+7)

To solve 8 = 2^5x+7, you would need to re-write 8 as what base?

• 8

• 4

• 2

• Cannot be determined

Solve:

log₂(x + 3)=5

• x=2

• x=29

• x=7

• x=32

Which is the correct way to rewrite,log₆(x-3)= 2, in order to solve.

• 6² = x-3

• 2⁶ = x - 3

• ln(2) = x-3

• e⁶ = x-3

Expand: $\log\left(\frac{x}{y}\right)$  

•  $\log x+\log y$  
  

•  $x\log y$  
  

•  $\log(x-y)$  
  

•  $\log x-\log y$  
  

Expand: $\ln\left(\frac{2x^2y}{z^4}\right)$  

•  $\ln2+2\ln x+\ln y+4\ln z$  
  

•  $\ln2+2\ln x+\ln y-4\ln z$  
  

•  $2\ln(2xy)-4\ln z$  
  

•  $2\ln2x+\ln y-4\ln z$  
  

 $\log(4x)$  

•  $\log4-\log x$  
  

•  $\log4+\log x$  
  

•  $4\log x$  
  

•  $x\log4$  
  

Rewrite $\log_vn=a$  in exponential form.

•  $v^a=n$  
  

•  $n^a=v$  
  

•  $v^n=a$  
  

•  $a^n=v$