K. Williams- Week 34 Day 6 Factoring Quadratics

Solve by factoring. Factor using both the AC METHOD and x-boxing method.

x² + 15x + 44 = 0

• {-8, 2}

• {-7, 5}

• {-11, -4}

• {-11}

Tags

CCSS.HSA-REI.B.4B

Solve by factoring. (what do they have in common)

n² - 2n = 0

• n = 2 and 0

• n = -2 and 0

• n = 2

• n = 0

Tags

CCSS.HSA-REI.B.4B

Solve by factoring.

b² + 2b - 24 = 0 (hint: find the zeros) FACTOR! Factor using both the AC METHOD and x-boxing method.

• x = 6 or x = -4

• x = -6 or x = -4

• x = 6 or x = 4

• x = -6 or x = 4

Tags

CCSS.HSA-REI.B.4B

Factor:  $16-x^4y^2$  

•  $\left(4+xy\right)\left(4-xy\right)$  

•  $\left(8+x^2y\right)\left(8-x^2y\right)$  

•  $\left(8+xy\right)\left(8-xy\right)$  

•  $\left(4+x^2y\right)\left(4-x^2y\right)$  

Tags

CCSS.HSA.APR.C.4

Find the factors of 4x²-16x-9 Factor using both the AC METHOD and x-boxing method.

• (2x-9)(2x+1)

• (2x+9)(2x-1)

• (4x-1)(x+9)

• (x+1)(4x-9)

What are the factors of 3x²-17x+10? Factor using both the AC METHOD and x-boxing method.

• (x-5)(3x-2)

• (x+5)(3x+2)

• (3x-5)(x-2)

• (x+5)(3x-2)

Find the factors of 5x²+20x+20. Factor using both the AC METHOD and x-boxing method.

• 5(x+2)(x+2)

• 5(x-2)(x-2)

• 5(x+2)(x-2)

• (5x+2)(x+2)

What are the factors of 3x²-17x+10? Factor using both the AC METHOD and x-boxing method.

• (x-5)(3x-2)

• (x+5)(3x+2)

• (3x-5)(x-2)

• (x+5)(3x-2)

Factor: 4x²-16x-9. Factor using both the AC METHOD and x-boxing method.

• (2x-9)(2x+1)

• (2x+9)(2x-1)

• (4x-1)(x+9)

• (x+1)(4x-9)

Factor using both the AC METHOD and x-boxing method. 3x²+9x-30=0

• x= 2, -5

• x= 5, -2

• x= -5, -2

Tags

CCSS.HSA-REI.B.4B