Quadratic Formula

Check all of the equations that are in standard form.

• $x^2=6x-7$

• $x^2-9x+1=0$

• $\left(x-5\right)\left(x+2\right)=0$

• $-2x^2+x+1=0$

• $\left(x-5\right)^2=9$

 $3x^2-5x+2$  

What is the value of b?

 $3x^2+4=-2x$  

If you are going to solve this using the quadratic formula, what should be your first step?

• subtract 4 from both sides
  

• add 2x to both sides
  

• divide both sides by 3
  

• take half of 4 and square it
  

 $x=\frac{-3\pm\sqrt{\left(3\right)^2-4\left(1\right)\left(2\right)}}{2\left(1\right)}$ 

What does x equal?

• x = 1 or -2
  

• x = -1 or 2
  

• x = 1 or 2
  

• x = -1 or -2
  

 $2x^2-5x+3\ =\ 0$  

Which of these is set up correctly?

•  $x\ =\frac{-\left(-5\right)\pm\sqrt{\left(-5\right)^2-4\left(2\right)\left(3\right)}}{2\left(2\right)}$  

•  $x=\frac{-5\pm\sqrt{5^2-4\left(2\right)\left(3\right)}}{2\left(2\right)}$  

•  $x=\frac{-5\pm\sqrt{\left(-5\right)^2-4\left(2\right)\left(3\right)}}{2\left(2\right)}$  

 $\frac{7-\sqrt{9}}{2}$  = ?

 $\frac{-6\pm\sqrt{8}}{2}$ 

Which one of these is NOT equivalent to this expression?

•  $\frac{-6\pm2\sqrt{2}}{2}$  

•  $-3\pm\sqrt{2}$  

•  $-3\pm\sqrt{8}$  

 $x^2+4x+3=0$  Would this quadratic equation have 2 solutions, 1 solution, or no solutions?

• No solutions
  

• 1 solution
  

• 2 solutions
  

 $x^2-8x+2=0$  

Which method would you choose to solve this equation? (There is not a "right" answer.)

• Graphing

• Factoring & Zero Product Property
  

• Complete the Square
  

• Quadratic Formula