What is the inverse of the given coordinates: (1, 2) (3, 8) (-3, 6)

• (1, 2) (3, 8) (-3, 6)
• (1, 2) (8, 3) (-3, 6)
• (-1, -2) (-3, -8) (3, -6)
• (2, 1) (8, 3) (6, -3)

Tags

CCSS.HSF-BF.B.4C

Find the inverse of
f(x) = 1/4x - 7

• f^-1(x) = 4x + 7
• f^-1(x) = -4x + 28
• f^-1(x) = -4x - 7
• f^-1(x) = 4x + 28

Tags

CCSS.HSF-BF.B.4A

Are the following inverses of each other?

• True
• False

Tags

CCSS.HSF-BF.B.4B

When finding the inverse of a relation, 
1st you replace f(x) with y
2nd switch the x's and y's
What do you do next?

• solve for y
• replace y with f^-1(x)
• solve for x
• find the greatest common factor

Tags

CCSS.HSF-BF.B.4A

Are these the graphs of two inverse functions?

• Yes
• No
• No way to tell

Tags

CCSS.HSF.BF.B.4

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.9

Find the inverse of f(x) = 3x +8

• f^-1(x) = 3(x-8)

• f^-1(x) = (8x-1)/3

• f-1(x) =x/3 - 8/3

• f^-1(x) = (x+8)/3

Tags

CCSS.HSF-BF.B.4A

Find the inverse of f(x) = -4x - 12

• f^-1(x) = 4x - 3
• f^-1(x) = -1/4x - 3
• f^-1(x) = 1/4x + 3
• f^-1(x) = -4x - 3

Tags

CCSS.HSF-BF.B.4A

 $f\left(x\right)\ =\ 2x\ -\ 6$  Find the inverse of the function.

•  $f^{-1}\left(x\right)\ =\frac{x}{2}+3$  

•  $f^{-1}\left(x\right)\ =\ \frac{x}{2}-\ 3$  

•  $f^{-1}\left(x\right)\ =\ \frac{x}{2}\ +\ 6$  

•  $f^{-1}\left(x\right)\ =\frac{x}{2}-\ 6$  

Tags

CCSS.HSF-BF.B.4A

 $f\left(x\right)\ =\frac{x}{3}+2$  Find the inverse.

•  $f^{-1}\left(x\right)\ =\ 3x\ -\ 2$  

•  $f^{-1}\left(x\right)\ =\ 3\left(x\ -2\right)$  

•  $f^{-1}\left(x\right)\ =\ 3x\ +\ 6$  

•  $f^{-1}\left(x\right)\ =\ \frac{x}{3}\ -\frac{2}{3}$  

Tags

CCSS.HSF-BF.B.4A

 $f\left(x\right)\ =\ \frac{1}{3}x\ -5$  Find the inverse.

•  $f^{-1}\left(x\right)\ =\ \frac{x}{3}\ +15$  

•  $f^{-1}\left(x\right)\ =\ \frac{x}{3}+\frac{5}{3}$  

•  $f^{-1}\left(x\right)\ =\ 3x\ +\ 5$  

•  $f^{-1}\left(x\right)\ =\ 3x\ +\ 15$  

Tags

CCSS.HSF-BF.B.4A