Grade 6 EOG Review

Which would you solve first in this expression?  $\left(5^2-10\right)\div5\times2^3$  

•  $2^3$  

•  $5^2$  

•  $5\times2$  

•  $10\div5$  

 $\left(5^2-10\right)\div5\times2^3$  

In this expression, what is the value of the last term?

• 10

• 25

• 6

• 8

 $\left(5^2-10\right)\div5\times2^3$  
Solve inside the parenthesis.

• 0

• 15

• 25

• 35

 $\left(5^2-10\right)\div5\times2^3$  
Solve.

• 24

• 18

• 1/2

• 0

HOW WOULD YOU SOLVE THIS PROBLEM?

Ja'Maya had a job during summer vacation. She earned $8.50 an hour. She worked 5 hours a week for 8 weeks. How much money did she earn?

• Add all the numbers together.

• Multiply 5 and 8, then add $8.50.

• Multiply the product of 5 and 8 by $8.50.

• Multiply $8.50 by 5 hours, then divide by 8.

SOLVE.

Ja'Maya had a job during summer vacation. She earned $8.50 an hour. She worked 5 hours a week for 8 weeks. How much money did she earn?

• $48.50

• $110.50

• $340

• $3,000

 $25x+10y$  

What is the GCF of the two coefficients in the expression?

• 2

• 5

• 10

• 25

 $25x+10y$  
Which expression is equivalent?

•  $5\left(5x+2y\right)$  

•  $5\left(5x+10y\right)$  

•  $5\left(20x+5y\right)$  

•  $5\left(20x+10y\right)$  

 $45+5x-x+\frac{3}{4}$  
How many terms are in the expression?

• two

• three

• four

• five

 $45+5x-x+\frac{3}{4}$  
Simplify this expression.

•  $45+4x+\frac{3}{4}$  
  

•  $50\ \frac{3}{4}x$  

•  $50x-\frac{3}{4}x$  

•  $45\ \frac{3}{4}+4x$