Macdonald- Solving systems by substitution

y =6x-11

-2x-3y= -7

• (-2,-1)

• (2,1)

• (-1,2)

• (-2,1)

2x-3y= -1

y =x-1

y =-3x+5

5x-4y= -3

• (-1,2)

• (1,-2)

• (2,1)

• (1,2)

-4x+y= 6

-5x-y= 21

• (3,-6)

• (-3,4)

• (-3,-6)

• (3,-4)

-7x-2y= -13

x-2y= 11

-5x+y= -2

-3x+6y= -12

• (0,-2)

• (6,-2)

• (0,2)

• (-6,2)