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2倍角・半角の公式

Authored by 中嶋 裕哉

Mathematics

11th Grade

Used 12+ times

2倍角・半角の公式
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8 questions

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1.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 sin2α=?\sin2\alpha=?  

 2sinαcosα2\sin\alpha\cos\alpha  

 cos2αsin2α\cos^2\alpha-\sin^2\alpha  

 12sin2α1-2\sin^2\alpha  

 2cos2α12\cos^2\alpha-1  

2.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 tan2α=?\tan2\alpha=?  

2tanα1tan2α\frac{2\tan\alpha}{1-\tan^2\alpha}

2tanα1+tan2α\frac{2\tan\alpha}{1+\tan^2\alpha}

tanα1tan2α\frac{\tan\alpha}{1-\tan^2\alpha}

tanα1+tan2α\frac{\tan\alpha}{1+\tan^2\alpha}

3.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 sin2α2=?\sin^2\frac{\alpha}{2}=?  

 1cosα2\frac{1-\cos\alpha}{2}  

 1+cosα2\frac{1+\cos\alpha}{2}  

 1cosα1+cosα\frac{1-\cos\alpha}{1+\cos\alpha}  

 1+cosα1cosα\frac{1+\cos\alpha}{1-\cos\alpha}  

4.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 cos2α2=?\cos^2\frac{\alpha}{2}=?  

 1cosα2\frac{1-\cos\alpha}{2}  

 1+cosα2\frac{1+\cos\alpha}{2}  

 1cosα1+cosα\frac{1-\cos\alpha}{1+\cos\alpha}  

 1+cosα1cosα\frac{1+\cos\alpha}{1-\cos\alpha}  

5.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 tan2α2=?\tan^2\frac{\alpha}{2}=?  

 1cosα2\frac{1-\cos\alpha}{2}  

 1+cosα2\frac{1+\cos\alpha}{2}  

 1cosα1+cosα\frac{1-\cos\alpha}{1+\cos\alpha}  

 1+cosα1cosα\frac{1+\cos\alpha}{1-\cos\alpha}  

6.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

 cos2α=?\cos2\alpha=?  

 2sinαcosα2\sin\alpha\cos\alpha  

 cos2αsin2α\cos^2\alpha-\sin^2\alpha  

 1sin2α1-\sin^2\alpha  

 2cos2α+12\cos^2\alpha+1  

7.

MULTIPLE CHOICE QUESTION

5 sec • 1 pt

cos2α=?\cos2\alpha=?

2sinαcosα2\sin\alpha\cos\alpha

cos2α+sin2α\cos^2\alpha+\sin^2\alpha

12sin2α1-2\sin^2\alpha

12cos2α1-2\cos^2\alpha

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