Analyzing Quadratics and Line/Curve of Best Fit

A scientist dropped an object from a height of 200 feet. She recorded the height of the object in 0.5-second intervals. Her data is shown.

Based on a quadratic model, which best approximates the height at 3 seconds?

• 52 feet

• 55 feet

• 65 feet

• 80 feet

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.CED.A.2

CCSS.HSA.SSE.A.1

The table shows the average braking distance of a car at various speeds.  Use a quadratic model to predict the breaking distance at 70mph.  

• 245 ft
• 225 ft
• 285 ft
• 265 ft

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

CCSS.HSF.BF.A.1

CCSS.HSF.LE.A.2

Using the quadratic curve of best fit, find the height of the ball when it traveled a distance of 10 feet.

• 12.8 ft

• 13.3 ft

• 11.1 ft

• 17 ft

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

CCSS.HSA.SSE.A.1

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

The table shows the height of a tree for various years after it was planted. Using the line of best fit, how tall would the tree be 30 years after it was planted?

• 22 feet

• 23 feet

• 36 feet

• 37 feet

Tags

CCSS.HSF.LE.B.5

Look at the data in this table.

Which equation most closely represents the line of best fit for this data?

• $y=1.77x+0.13$

• $y=0.56x-0.05$

• $y=0.5x$

• $y=2x$

Tags

CCSS.8.EE.B.5

The number of complaints a company received at the end of each of six weeks is shown in this table.

Based on the line of best fit, how many complaints should the company expect at the end of week 8?

• 75

• 91

• 96

• 110

Tags

CCSS.HSA.CED.A.2

CCSS.HSA.REI.D.10

CCSS.HSF.IF.B.4

CCSS.HSF.IF.C.7

CCSS.HSS.ID.B.6

CCSS.HSS.ID.C.7

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. How high is the object after 1 second?

• 143 meters
• 49 meters
• 238 meters
• 110 meters

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.1

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When does the object hit the ground?

• about 7.3 seconds
• about 3.4 seconds
• about 7.8 seconds
• 8 seconds

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When does it reach its maximum height?

• about 7.3 seconds
• about 3.4 seconds
• about 7.8 seconds 
• 8 seconds

Tags

CCSS.HSA.REI.B.4

CCSS.HSA.REI.D.10

An object is launched at 19.6 meters per second (m/s) from a platform. The equation for the object's height s at time t seconds after launch is s(t)=-16t²+110t+49, where s is in meters. When is the object 20 meters high?

• about 7.13 seconds
• about 3.4 seconds
• about 7.8 seconds
• about 8 seconds

Tags

CCSS.HSA.CED.A.1

CCSS.HSA.REI.B.4