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Turunan Fungsi

Authored by Henry Akmal

Mathematics

12th Grade

Used 2+ times

Turunan Fungsi
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10 questions

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1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Turunan pertama dari y=2x34x2+2y=2x^3-4x^2+2  adalah  yy'  

 6x28x+26x^2-8x+2  

 6x2+8x+26x^2+8x+2  

 6x38x26x^3-8x^2  

 6x28x6x^2-8x  

 6x2+8x6x^2+8x  

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Fungsi f ditentukan oleh  f(x)=2x3+3x24x10f\left(x\right)=2x^3+3x^2-4x-10 . Nilai dari  f(1)=....f'\left(-1\right)=....   

 16-16  

 12-12  

 10-10  

 8-8  

 4-4  

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Diberikan fungsi f(x)=2x3f\left(x\right)=2x^3 dan  g(x)=3x2+12xg\left(x\right)=3x^2+12x . Jika  f(a)=g(a)f'\left(a\right)=g'\left(a\right) , nilai a yang memenuhi adalah ....   

 2 atau 1-2\ atau\ 1  

 1 atau 2-1\ atau\ 2  

 1 atau 21\ atau\ 2  

 2 atau 32\ atau\ 3  

 3 atau 43\ atau\ 4  

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

 Turunan pertama dari f(x)=(2x2+x+1)5f\left(x\right)=\left(2x^2+x+1\right)^5 adalah ....

 (2x2+x+1)4\left(2x^2+x+1\right)^4  

 5x(2x2+x+1)45x\left(2x^2+x+1\right)^4  

 (20x+1)(2x2+x+1)4\left(20x+1\right)\left(2x^2+x+1\right)^4  

 (4x+1)(2x2+x+1)4\left(4x+1\right)\left(2x^2+x+1\right)^4  

 (20x+5)(2x2+x+1)4\left(20x+5\right)\left(2x^2+x+1\right)^4  

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Turunan dari f(x)=2x14x+3,x34f\left(x\right)=\frac{2x-1}{4x+3},x\ne\frac{3}{4}  adalah ....

 f(x)=10(4x+3)2f'\left(x\right)=\frac{-10}{\left(4x+3\right)^2}  

 f(x)=5(4x+3)2f'\left(x\right)=\frac{-5}{\left(4x+3\right)^2}  

 f(x)=2(4x+3)2f'\left(x\right)=\frac{2}{\left(4x+3\right)^2}  

 f(x)=5(4x+3)2f'\left(x\right)=\frac{5}{\left(4x+3\right)^2}  

 f(x)=10(4x+3)2f'\left(x\right)=\frac{10}{\left(4x+3\right)^2}  

6.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Turunan pertama dari f(x)=x235x+2f\left(x\right)=\frac{x^2-3}{5x+2}  adalah  f(x)f'\left(x\right) . Nilai dari  f(0)=....f'\left(0\right)=....   

 174-\frac{17}{4}  

 154-\frac{15}{4}  

 64\frac{6}{4}  

 154\frac{15}{4}  

 174\frac{17}{4}  

7.

MULTIPLE CHOICE QUESTION

2 mins • 1 pt

Grafik fungsi  f(x)=23x3  x2 12x + 10 = 0f\left(x\right)=\frac{2}{3}x^3\ -\ x^2\ -12x\ +\ 10\ =\ 0  naik untuk interval...

 3<x<23<x<-2  

 2<x<3-2<x<3  

 x<2 atau x>3x<2\ atau\ x>-3  

 x<2 atau x>3x<-2\ atau\ x>3  

 x<3 atau x>2x<-3\ atau\ x>-2  

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