Decision and Case Control Statements in C

What will be the output of the following C code?

#include <stdio.h>

void main()

{

int x = 5;

if (x < 1)

printf("hello");

if (x == 5)

printf("hi");

else

printf("no");

}

• hi

• hello

• no

• error

What will be the output of the following C code?

#include <stdio.h>

int main()

{

int x = 0;

if (x == 1)

if (x == 0)

printf("inside if\n");

else

printf("inside else if\n");

else

printf("inside else\n");

}

• inside if

• inside else if

• inside else

• compile time error

What will be the output of the following C code?

#include <stdio.h>

int main()

{

int x = 0;

if (x == 1)

if (x >= 0)

printf("true\n");

else

printf("false\n");

}

• Depends on the compiler

• No print statement

• True

• False

The output of the following segment is

int k, n=20;

k=(n>5?(n<=10?100:200):500);

printf("%d",n);

• 100

• 200

• 300

• 20

What will be the output of the following C code?

#include <stdio.h>

int main()

{

int a = 1, b = 1;

switch (a)

{

case a*b:

printf("yes ");

case a-b:

printf("no\n");

break;

}

}

• yes

• no

• yes no

• compile time error

What is the result after execution of the following code if a is 10, b is 5, and c is 10?

if ((a > b) && (a <= c))

a = a + 1;

else

c = c+1;

• a = 10, c = 10

• a = 11, c = 10

• a = 10, c = 11

• a = 11, c = 11

Output of the following code

#include <stdio.h>

int main()

{ int i = 0;

switch (i)

{

case '0': printf("Geeks");

break;

case '1': printf("Quiz");

break;

default: printf("GeeksQuiz");

}

return 0;

}

• Geeks

• Quiz

• GeeksQuiz

• None of the above

How will you print \n on the screen?

• printf("\n");

• echo "\\n";

• printf('\n');

• printf("\\n");

int main()

{

if(0);

printf("Hello");

printf("Hi");

return 0;

}

• Hi

• Hello

• HelloHi

• Compilation Error

what is output of following code?

#include <stdio.h>

int main( )

{

if(printf("C programming is"))

{

printf("Easy");

}

else

{

printf("Hard");

}

return 0;

}

• C Programming Easy

• Easy

• Hard

• None of these