Solving Quadratics with Complex Solutions

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7

When you are solving for the roots/zeros of a quadratic function, which equation should you use?

• $D=b^2-4ac$

• $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Tags

CCSS.HSA-REI.B.4B

When you are solving for the amount of solutions, which equation should you use?

• $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

• $D=b^2-4ac$

Tags

CCSS.HSA-REI.B.4B

Find the roots of the following quadratics:

 $2x^2+6x=11$  

•  $\left\{\frac{11}{2},8\right\}$  

•  $\left\{-2\sqrt{31},\ -\sqrt{31}\right\}$  

•  $\left\{\frac{-3+\sqrt{31}}{2},\ \frac{-3-\sqrt{31}}{2}\right\}$  

• No Solutions

Tags

CCSS.HSA-REI.B.4B

If the discriminant equals 0, then the quadratic has:

• 1 Real Solution
• 2 Real Solutions
• 2 Non Real Solutions

• No Real Solution

Tags

CCSS.HSA-REI.B.4B

What is the discriminant of the quadratic formula?

• b²-4a
• b²-4ac
• b-4ac
• b²-ac

Tags

CCSS.HSA-REI.B.4B

If the discriminant is negative, then the quadratic has:

• 1 Real Solution
• 2 Real Solutions
• Half a Solution
• No Real Solutions

Tags

CCSS.HSA-REI.B.4B

If the discriminant is positive, then the quadratic has:

• 1 Real Solution
• 2 Real Solutions
• Half a Solution
• No Real Solution

Tags

CCSS.HSA-REI.B.4B

Put 2x² = 3x - 4 in standard form

• 2x² + 3x - 4 = 0
• 2x² - 3x + 4 = 0
• 2x² - 3x - 4 = 0
• 2x² + 3x + 4 = 0

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.CED.A.1

CCSS.HSA.SSE.A.2

Solve x² - 5x + 10 = 0

• (5 - i√15)/2  ,  (5 + i√15)/2
• (5 - √15)/2  ,  (5 + √15)/2
• (5 - i√65)/2  ,  (5 + i√65)/2
• (5 - √65)/2  ,  (5 + √65)/2

Tags

CCSS.HSA-REI.B.4B

CCSS.HSN.CN.C.7