GARIS LURUS

Authored by MPDCA Sekolah Menengah

Mathematics

8th Grade - Professional Development

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10 questions

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MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Kecerunan garis lurus $3y+4x+3=0$ ialah

$-\frac{4}{3}$

$-\frac{3}{4}$

$-4$

$-3$

Answer explanation

$y=-\frac{4}{3}x-\frac{3}{3}$ bandingkan dengan
$y=mx+c$
$m=-\frac{4}{3}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Pintasan -x bagi $\frac{x}{5}+\frac{y}{3}=1$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hitung jarak di antara pasangan titik (2, –3) dan (4, –3)

-6

-2

Answer explanation

Jarak di antara titik $4-2=2$ unit

MULTIPLE SELECT QUESTION

45 sec • 1 pt

Rumus kecerunan ialah

$m=\frac{y_1-y_2}{x_1-x_2}$

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=-\frac{y}{x}$

$m=-\frac{pintasan\ -\ y}{pintasan\ -\ x}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tentukan kecerunan garis lurus PQ

$\frac{5}{3}$

$-\frac{5}{3}$

$\frac{3}{5}$

$-\frac{3}{5}$

Answer explanation

$Kecerunan\ =\frac{Jarak\ mencancang}{Jarak\ mengufuk}=\frac{3}{5}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Tentukan kecerunan bagi garis lurus berikut

$\frac{4}{3}$

$\frac{3}{4}$

$-\frac{3}{4}$

$-\frac{4}{3}$

Answer explanation

$Kecerunan=-\frac{pintasan\ -\ x}{pintasan\ -\ y}=-\frac{4}{3}$

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hitung koordinat titik tengah bagi garis lurus AB dengan A(2, 5) dan B(2, 1).

(2 , 3)

(-2 , 3)

(2 , -3)

(-2 , -3)

Answer explanation

$\left(\frac{2+2}{2},\frac{5+1}{2}\right)=\left(2,\ 3\right)$

MULTIPLE SELECT QUESTION

45 sec • 1 pt

$2y+5=-3x$
Pintasan - y bagi garis lurus di atas ialah

$-5$

$\frac{5}{2}$

$-2.5$

$-\frac{5}{2}$

Answer explanation

$y=-\frac{3}{2}x-\frac{5}{2}$ bandingkan dengan
$y=mx+c$ ;

c = pintasan - y
$c=-\frac{5}{2}=-2.5$

10.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Hitung jarak di antara pasangan titik (-3 , 6) dan (-3 , 4)

-6

-2

Answer explanation

Jarak di antara titik $6-4=2$ unit

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GARIS LURUS

Kecerunan garis lurus 3y+4x+3=03y+4x+3=03y+4x+3=0 ialah

y=−43x−33y=-\frac{4}{3}x-\frac{3}{3}y=−34​x−33​ bandingkan dengan y=mx+cy=mx+cy=mx+c m=−43m=-\frac{4}{3}m=−34​

Pintasan -x bagi x5+y3=1\frac{x}{5}+\frac{y}{3}=15x​+3y​=1

Hitung jarak di antara pasangan titik (2, –3) dan (4, –3)

Jarak di antara titik 4−2=24-2=24−2=2 unit

Rumus kecerunan ialah

Tentukan kecerunan garis lurus PQ

Kecerunan =Jarak mencancangJarak mengufuk=35Kecerunan\ =\frac{Jarak\ mencancang}{Jarak\ mengufuk}=\frac{3}{5}Kecerunan =Jarak mengufukJarak mencancang​=53​

Tentukan kecerunan bagi garis lurus berikut

Kecerunan=−pintasan − xpintasan − y=−43Kecerunan=-\frac{pintasan\ -\ x}{pintasan\ -\ y}=-\frac{4}{3}Kecerunan=−pintasan − ypintasan − x​=−34​

Hitung koordinat titik tengah bagi garis lurus AB dengan A(2, 5) dan B(2, 1).

(2+22,5+12)=(2, 3)\left(\frac{2+2}{2},\frac{5+1}{2}\right)=\left(2,\ 3\right)(22+2​,25+1​)=(2, 3)

2y+5=−3x2y+5=-3x2y+5=−3x Pintasan - y bagi garis lurus di atas ialah

y=−32x−52y=-\frac{3}{2}x-\frac{5}{2}y=−23​x−25​ bandingkan dengan y=mx+cy=mx+cy=mx+c ; c = pintasan - y c=−52=−2.5c=-\frac{5}{2}=-2.5c=−25​=−2.5

Tentukan titik tengah bagi garis lurus PQ.

Hitung jarak di antara pasangan titik (-3 , 6) dan (-3 , 4)

Jarak di antara titik 6−4=26-4=26−4=2 unit

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Kecerunan garis lurus $3y+4x+3=0$ ialah

$y=-\frac{4}{3}x-\frac{3}{3}$ bandingkan dengan
$y=mx+c$
$m=-\frac{4}{3}$

Pintasan -x bagi $\frac{x}{5}+\frac{y}{3}=1$

Jarak di antara titik $4-2=2$ unit

$Kecerunan\ =\frac{Jarak\ mencancang}{Jarak\ mengufuk}=\frac{3}{5}$

$Kecerunan=-\frac{pintasan\ -\ x}{pintasan\ -\ y}=-\frac{4}{3}$

$\left(\frac{2+2}{2},\frac{5+1}{2}\right)=\left(2,\ 3\right)$

$2y+5=-3x$
Pintasan - y bagi garis lurus di atas ialah

$y=-\frac{3}{2}x-\frac{5}{2}$ bandingkan dengan
$y=mx+c$ ;

c = pintasan - y
$c=-\frac{5}{2}=-2.5$

Jarak di antara titik $6-4=2$ unit