Post Lab 3

Given the data of volume of NaOH solution in the titration process. What is the value of x and y?

Calculate the average volume of NaOH solution.

Given data of NaOH reading for the reaction between NaOH and HCl. The concentration of NaOH is 1.0 M.

Determine the number moles of HCl for this reaction.

• 2.173 x 10^-2

• 2.200 x 10^-2

• 2.273 x 10^-2

• 2.173 x 10^-1

By referring to the chemical reaction between HCl and metal M in Part B, identify the limiting reactant.

Back-titration method experiment is carried out to determine the molar mass of metal Y. Initial number mole of HCl in conical flask is 2.173 x 10^-2.

After the metal Y is added to HCl, the resulting solution is then titrated with NaOH solution. If 16.30 mL of 1.0 M NaOH is required for this titration, calculate the number moles of HCl reacted with M?

5.43 x 10^-3 moles of HCl is reacted with 0.071g of metal X and produced XCl₂ and hydrogen gas. Calculate the molar mass of metal X.

By using the above data, calculate the average molar mass of M.

From the calculation of experiment 3 (refer to lab manual), metal of M is _______________

• Sodium

• Aluminium

• Magnesium

• Calcium

Element in group 2 also known as

Charge of element in group 2 is