Geometry Review 2nd try

What type of figure is this?

• line

• line segment

• ray

• angle

Tags

CCSS.4.G.A.1

Identify this picture. 

• ray AB
• line AB
• line segment AB
• point AB

Tags

CCSS.HSG.CO.A.1

Name the figure

• Segment CD
• Segment DC
• Ray DC
• Line CD

Tags

CCSS.HSG.CO.A.1

Which of the following is the correct midpoint formula given two endpoints (x₁, y₁) and (x₂, y₂)?

• 
• 
• 
• 

Tags

CCSS.HSG.GPE.B.6

Find the midpoint of the segment on the graph. (Hover over picture to expand)

• (2,3)

• (-1,2)

• (5,-3)

• (3,2)

Tags

CCSS.HSG.GPE.B.6

Find the midpoint of the line segment with the given endpoints (-2,-6) and (8,8)

• (-4,8)

• (18,22)

• (3,1)

• (-5,-7)

Tags

CCSS.HSG.GPE.B.6

How is the distance formula correctly written:

• $d\ =\ \sqrt{\left(y_{1\ }-\ y_2\right)^2\ -\left(x_{2\ }-\ x_1\right)^2}\$

• $d\ =\ \sqrt{\left(x_{2\ }-\ x_1\right)^2\ +\ \left(y_{2_{\ }}-\ y_1\ \right)^2}$

• d = $\sqrt{\left(x\right)^2-\ \left(y\right)^2}$

Tags

CCSS.HSG.GPE.B.7

A(3,1) B(-2,-1) written correctly is:

• $\sqrt{\left(-2-3\right)^2\ +\ \left(-1-1\right)^2}$

• $\sqrt{\left(1-3\right)^2\ +\ \left(-1-2\right)^2}$

• $\sqrt{\left(-2-3\right)^2\ -\ \left(-1-1\right)^2}$

Tags

CCSS.HSG.GPE.B.7

What is the distance between AB

• 0

• 8

• 9

• 7

Tags

CCSS.6.G.A.3

Find the distance.

• 9.7
• 10.7
• 11.7
• 12.7

Tags

CCSS.HSG.GPE.B.7