Kinematics Basic Practice

A car driving from rest goes to the store 500 meters away and accelerates at 0.4 m/s^2. The car takes 18 seconds to get there. Eventually, the car reaches 7.2 m/s.

What was the car's time interval for the trip?

• 500 m

• 0.4 m/s^2

• 18 s

• 7.2 m/s

Tags

NGSS.HS-PS2-1

From a height of 16 meters, a frisbee is thrown forward with a velocity of 4 m/s to the right. What was the frisbee's initial velocity going down?

• 16 m

• 4 m/s

• -9.8 m/s^2

• 0 m/s

A plane moving at 19 m/s lands on the runaway so that it can come to a rest. The plane accelerates at -0.6 m/s^2 over a displacement of 92 meters. What will the plane's final velocity be?

• 19 m/s

• 0 m/s

• -0.6 m/s^2

• 92 meters

Tags

NGSS.HS-PS2-1

Starting at 2 m/s, a wheel accelerates at a rate of 4.2 m/s^2 for 7 seconds.

To find the Final Velocity, which equation should you use?

• Vf = Vi + a*t

• (Vf+Vi) / 2 * t = d

• Vf ^2 = Vi ^2 + 2 * a * d

• d = Vi * t + 0.5 * a * t^2

Tags

NGSS.HS-PS2-1

If a scuba diver swims down with a starting velocity of 0.2 m/s and ends at a velocity of 1.6 m/s. The scuba diver swam for 7 seconds. Which equation should be used to find the Displacement?

• Vf = Vi + a*t

• (Vf+Vi) / 2 * t = d

• Vf ^2 = Vi ^2 + 2 * a * d

• d = Vi * t + 0.5 * a * t^2

A car driving from rest goes to the store 500 meters away and accelerates at 0.4 m/s^2. The car takes 18 seconds to get there. Eventually, the car reached 7.2 m/s.

What was the car's Displacement for the trip?

• 500 m

• 0.4 m/s^2

• 18 s

• 7.2 m/s

Starting at 8.4 m/s, a wheel adds velocity at a rate of 1.7 m/s^2 for 9 seconds. What was the Acceleration of the wheel?

• 8.4 m/s

• -9.8 m/s^2

• 1.7 m/s^2

• 9 s

Tags

NGSS.HS-PS2-1

A log rolls down a hill for 4 seconds and reaches the bottom after moving 200 meters. If the acceleration was at a rate of 3 m/s^2, what equation should be used to solve for the initial velocity going down?

• Vf = Vi + a*t

• (Vf+Vi) / 2 * t = d

• Vf ^2 = Vi ^2 + 2 * a * d

• d = Vi * t + 0.5 * a * t^2

Tags

NGSS.HS-PS2-1

A ball is thrown down a cliff with a starting velocity of 3.7 m/s and ends at a velocity of 42.9 m/s. The ball hits the ground after 4 seconds. What equation should be used to solve for Displacement

• Vf = Vi + a*t

• (Vf+Vi) / 2 * t = d

• Vf ^2 = Vi ^2 + 2 * a * d

• d = Vi * t + 0.5 * a * t^2

As an antelope bounds across the forest floor, it hears a predator in the bushes and accelerate away at a rate of 7.1 m/s^2. After hopping for 18 meters, the antelope reaches 20 m/s and manages to escape from being eaten. What equation should be used to solve for the Initial Velocity?

• Vf = Vi + a*t

• (Vf+Vi) / 2 * t = d

• Vf ^2 = Vi ^2 + 2 * a * d

• d = Vi * t + 0.5 * a * t^2

Tags

NGSS.HS-PS2-1