Lesson 7 - Day 4 (Distributive Property)

What would the DISTRIBUTIVE property equation look like AFTER the array has been broken apart?

• (8 x 5) + (8 x 4)

• (8 x 2) + (8 x 4)

• (5 x 5) + (5 x 4)

• (8 x 5 x 5 x 5)

Tags

CCSS.4.NBT.B.5

What is the equation for the ORIGINAL array BEFORE it was broken apart?

• 8 x 8

• 8 x 9

• 8 x 10

• 9 x 9

Tags

CCSS.3.OA.A.3

What is the DISTRIBUTIVE equation AFTER the array was broken apart? This time think top + bottom.

• (4 x 9) + (4 - 0)

• (2 x 9) + (1 x 9)

• (4 x 4) + (4 x 4)

• (4 x 9) + (4 x 9)

Tags

CCSS.6.NS.B.4

What number would complete the equation?             6 x __ = 54

Tags

CCSS.2.OA.C.4

What would the distributive equation be to match each smaller array?

• (6 x 5) + (6 x 4)

• (6 x 2) + (6 x 4)

• (2 x 5) + (2 x 4)

• 6 x 5 x 5

Tags

CCSS.6.NS.B.4

What would the products (answers) be for the two smaller arrays. These are the numbers we will add back together to get the final product.

• 30 + 24

• 15 + 24

• 24 + 24

• 30 + 20

Tags

CCSS.3.OA.B.5

What is one way to split 2 x 9 using the distributive property?

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• 
• 

Tags

CCSS.3.OA.B.5

Which array shows 4 x (5+4)?

• 
• 
• 

Tags

CCSS.2.OA.C.4

What is the original equation AND the distributive equation?

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• 
• 
• 

Tags

CCSS.4.NBT.B.5

What is the equation for the ORIGINAL array before it was broken apart?

• 8 x 7

• 8 x 8

• 8 x 9

• 8 x 10

Tags

CCSS.2.OA.C.4