Solving Quadratics with factoring and square roots

Write a quadratic equation in standard form with the given roots: 1, 7

• x² - 6x - 7
• x² + 8x + 7
• x² - 8x + 7
• x² + 6x - 7

Factor the polynomial: 
x² - 25

• (x + 5)(x - 5)
• (x - 25)(x + 1)
• (x - 1)(x + 25)
• (x + 5)(x + 5)

Tags

CCSS.HSA.APR.C.4

Solve by factoring:
x² - 6x + 5 = 0

• -6, -1
• -5, -1 
• 1, 6
• 5, 1

Tags

CCSS.HSA-REI.B.4B

What is the first step to solving x²-9x=10 with Factoring?

• Look for 2 numbers whose sum is -9 and product is 10.

• Subtract 10 from both sides.

• Divide -9 by 2 and square the answer.

• Look for 2 numbers whose sum is 10 and product is -9.

Tags

CCSS.HSA-REI.B.4B

Using the Square Root method, what is the first step to solving the equation: 8x²+9=10

• Subtract 10 from both sides

• Divide by 8

• Subtract 9 from both sides

• Take the square root of both sides.

Tags

CCSS.HSA-REI.B.4B

Suzie solves the equation below:
x² + 4x - 12 = 2
(x - 2)(x + 6) = 2, 
by setting x -2 = 0 and x + 6 = 0. 
Her solutions are x = 2 and x = -6.
Is Suzie correct? Why or why not?

• Yes, she factored correctly and then used the zero product property
• Yes, she factored correctly and then square rooted.
• No, she did factor correctly, but she can't use the zero product property as shown.
• No, she didn't factor correctly so the rest of her work is wrong. 

Tags

CCSS.HSA-REI.B.4B

Solve by factoring: 3x² + 5x + 2 = 0  

• x = -2/3 and x = -1
• x = -3/2 and x = -1
• x = 2/3 and x = 1
• x = 2/3 and x = -1

Tags

CCSS.HSA-REI.B.4B

Factor: 49x² - 100

• (49x + 100)(x - 1)
• (7x - 10)(7x + 10)
• (49x - 10)(x + 10)
• (7x -10)(7x - 10)

Tags

CCSS.HSA.APR.C.4

x² + 4 = 68

• ± 8
• ± √8
• 8
• ± 64

Tags

CCSS.8.EE.A.2

Solve by taking square roots:
5b² - 4 = 41

• b = 9, b = -9
• b = 3, b = -3
• b = 8, b = -8
• no solutionb

Tags

CCSS.HSA-REI.B.4B