Solving by factoring

Solve for a by factoring.
a² + 2a - 24 = 0

• a = -6, 4
• a = 6, -4
• a = 12, -2
• a = 8, -3

What is the next step in solving after getting the quadratic in factored form?

(x + 2)(x - 3) = 0

• Plug in zero for x

• Multiply the binomials

• FOIL

• Set each binomial factor equal to zero

Solve by factoring: x² + 3x - 18 = 0

• x = -3 and x = 6
• x = 3 and x = -6
• x = -9 and x = 2
• x = 9 and x = -2

x² + 15x + 44 = 0

• {-8, 2}
• {-7, 5}
• {-11, -4}
• {-11}

Factor
k² - 2k - 24

• (k+4)(k-6)
• (k+4)(k+6)
• (k+6)(k-1)
• (k-4)(k+6)

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Solve
x² + 2x - 24 = 0

• x = -6, x = 4
• x = 6, x = -4
• x = 12, x = -2
• x = 8, x = -3

Solve
x² + 9x + 20 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Solve
x² + 7x + 12 = 0

• x = -2, x = -10
• x = -3, x = -4
• x = -4, x = -5
• x = -4, x = -6

Solve
x² + 13x + 12 = 0

• x = -1, x = -12
• x = -1, x = -24
• x = -2, x = -6
• x = -2, x = -12