Kiểm tra thử giữa kì 1 Toán 8 năm 2021 - 2022

$$2x^3+x^2+x+1$$  

$$2x^3-x^2+x+1$$  

$$2x^3-x^2-x+1$$  

$$2x^3-x^2+x-1$$  

10cm

1cm

2cm

4cm

$$\left(2x+1\right)\left(x+1\right)$$  

$$\left(2x+1\right)\left(x-1\right)$$  

$$\left(2x-1\right)\left(x+1\right)$$  

$$\left(2x-1\right)\left(x-1\right)$$  

$$\frac{1}{9}+3y+9y^2$$  

$$\frac{1}{3}+3y+9y^2$$  

$$\frac{1}{9}+2y+9y^2$$  

$$\frac{1}{9}+2y+3y^2$$  

$$0,09-\frac{1}{4}x^2$$  

$$0,9-\frac{1}{4}x^2$$  

$$0,09+\frac{1}{4}x^2$$  

$$0,09-\frac{1}{2}x^2$$  

$$9$$  

27

-27

-9

$$a\left(x+y\right)\left(x-y+3\right)$$  

$$a\left(x+y\right)\left(x-y-3\right)$$  

$$x\left(x-y\right)\left(x-y-3\right)$$  

$$a\left(x-y\right)\left(x+y-3\right)$$  

AB//MN//DC

MN=DC

MN//DC

$$MN=\frac{1}{2}DC$$  

$$\left(x+1\right)\left(x-3\right)$$  

$$\left(x-1\right)\left(x-3\right)$$  

$$\left(x+1\right)\left(x+3\right)$$  

$$\left(x-1\right)\left(x+3\right)$$  

1cm

4cm

11cm

7cm