11.3 Part 2

If capacitor is fully charged, how much was the emf of the battery?

• 1.5 V

• 1.5 A

• 1.00 x 10^–13 J

• 0.13 x 10^–12 C

If we decrease the separation between the plates, what will happen to the capacitance?

• It will increase. (C inversely proportional to d)

• It will decrease. (C inversely proportional to d)

• It will increase. (C directly proportional to d)

• It will decrease. (C directly proportional to d)

If we decrease the separation between the plates, what will happen to the charge stored?

• It will stay the same. (charge can't be destroyed)

• It will increase. (C directly proportional to q)

• It will decrease. (C directly proportional to q)

If we decrease the separation between the plates, what will happen to the energy stored?

• It will stay the same. (charge can't be destroyed)

• It will increase. (E inversely proportional to C when q is constant)

• It will decrease. (E inversely proportional to C when q is constant)

If we decrease the separation between the plates, what will happen to the p.d. between the plates?

• It will stay the same. (charge can't be destroyed)

• It will increase.

  ( V = E • d )

• It will decrease.

  ( V = E • d )

If we add a dielectric material greater than 1.

What will happen to the capacitance?

• It will increase.

  (C directly proportional to dielectric)

• It will decrease.

  (C directly proportional to dielectric)

• It remains the same.

If we add a dielectric material greater than 1.

What will happen to the charge on the plates?

• It will increase.

  (q directly proportional to dielectric)

• It will decrease.

  (q directly proportional to dielectric)

• It remains the same.

If we add a dielectric material greater than 1.

What will happen to the stored energy?

• It will increase.

  (E is inversely proportional to C if q is constant)

• It will decrease.

  (E is inversely proportional to C if q is constant)

• It remains the same.

What is the p.d. on the plates after the capacitor is fully charged?

• Same as emf of the battery

• 1/2 C V²

• V = I • R