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TURUNAN FUNGSI TRIGONOMETRI

Authored by lia yuliana

Mathematics

11th Grade

Used 12+ times

TURUNAN FUNGSI TRIGONOMETRI
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10 questions

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1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 nilai dxdynilai\ \frac{\text{d}x}{\text{d}y}  dari fungsi y=2 sin 3x−3 cos 2x adalah …

2 cos 3x −3 sin 2x

6 cos 3x −3 sin 2x

2 cos 3x +3 sin 2x

6 cos 3x +6  sin 2x

−6 cos 3x − 6 sin 2x

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 jika sin⁡ x + cos⁡ xsin⁡ x , x≠0jika\ \frac{\sin\ x\ +\ \cos\ x}{\sin\ x}\ ,\ x\ne0  dan f'(x) adalah turunan f(x), maka f′(π/2)

 – 2

- 1

0

1

2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 turunan pertama dari y = cos⁡4x adalah ...turunan\ pertama\ dari\ y\ =\ \cos^4x\ adalah\ ...  

 ¼cos⁡3x¼\cos^3x  

 − ¼cos⁡3x-\ ¼\cos^3x  

 ¼sin⁡3x¼\sin^3x  

 −4sin⁡3xcos⁡x−4\sin^3x\cos x  

 −4cos⁡3x sin⁡x−4\cos^3x\ \sin x  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 diketahui  f(x) = sin⁡2(2x + 3)f\left(x\right)\ =\ \sin^2\left(2x\ +\ 3\right)  dan turunan pertama fungsi f(x) adalah f’(x). maka hasil dari f’(x) adalah …

– 4 sin (2x + 3) cos (2x + 3)

4 sin (2x + 3) cos (2x + 3)

– 2 sin (2x + 3) cos (2x + 3)

2 sin (2x + 3) cos (2x + 3)

4 sin (2x + 3)3 cos (2x + 3)

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Turunan pertama dari f(x) = x cotan 2x adalah …

2Cotan⁡2x–2xcosec⁡22x2Co\tan2x–2x\operatorname{cosec}^22x

2tan⁡2x–2xcosec⁡22x2\tan2x–2x\operatorname{cosec}^22x

2xCotan⁡2x–cosec⁡22x2xCo\tan2x–\operatorname{cosec}^22x

Cotan⁡2x–xcosec⁡22xCo\tan2x–x\operatorname{cosec}^22x

Cotan⁡2x–2xcosec⁡22xCo\tan2x–2x\operatorname{cosec}^22x

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 F(x)=cos⁡ x5 + sin⁡ x,maka nilai dari f’(π3)=…F(x)=\frac{\cos\ x}{5\ +\ \sin\ x},maka\ nilai\ dari\ f’(\frac{\pi}{3})=…  

 −8121\frac{-8}{121}  

 −14121\frac{-14}{121}  

 14121\frac{14}{121}  

 17121\frac{17}{121}  

 18121\frac{18}{121}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 F(x)=sin⁡2 xx,maka nilai dari f’(π3)=…F(x)=\frac{\sin^2\ x}{x},maka\ nilai\ dari\ f’(\frac{\pi}{3})=…  

 2x sin⁡ x  − cos⁡ x sin⁡2 xx2\frac{2x\ \sin\ x\ \ -\ \cos\ x\ \sin^2\ x}{x^2}  

 2 sin⁡ x cos⁡ x − sin⁡2 xx2\frac{2\ \sin\ x\ \cos\ x\ -\ \sin^2\ x}{x^2}  

 2x sin⁡ x cos⁡ x − sin⁡2 xx2\frac{2x\ \sin\ x\ \cos\ x\ -\ \sin^2\ x}{x^2}  

 x sin⁡2 x cos⁡ x − sin⁡ xx2\frac{x\ \sin^2\ x\ \cos\ x\ -\ \sin\ x}{x^2}  

 2x2x2 sin⁡  x cos⁡ x\frac{2x^2}{x^2\ \sin\ \ x\ \cos\ x}  

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