TURUNAN FUNGSI TRIGONOMETRI

TURUNAN FUNGSI TRIGONOMETRI

11th Grade

10 Qs

quiz-placeholder

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TURUNAN FUNGSI TRIGONOMETRI

TURUNAN FUNGSI TRIGONOMETRI

Assessment

Quiz

Mathematics

11th Grade

Hard

Created by

lia yuliana

Used 12+ times

FREE Resource

10 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 nilai dxdynilai\ \frac{\text{d}x}{\text{d}y}  dari fungsi y=2 sin 3x−3 cos 2x adalah …

2 cos 3x −3 sin 2x

6 cos 3x −3 sin 2x

2 cos 3x +3 sin 2x

6 cos 3x +6  sin 2x

−6 cos 3x − 6 sin 2x

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 jika sin x + cos xsin x , x0jika\ \frac{\sin\ x\ +\ \cos\ x}{\sin\ x}\ ,\ x\ne0  dan f'(x) adalah turunan f(x), maka f′(π/2)

 – 2

- 1

0

1

2

3.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 turunan pertama dari y = cos4x adalah ...turunan\ pertama\ dari\ y\ =\ \cos^4x\ adalah\ ...  

 ¼cos3x¼\cos^3x  

  ¼cos3x-\ ¼\cos^3x  

 ¼sin3x¼\sin^3x  

 4sin3xcosx−4\sin^3x\cos x  

 4cos3x sinx−4\cos^3x\ \sin x  

4.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 diketahui  f(x) = sin2(2x + 3)f\left(x\right)\ =\ \sin^2\left(2x\ +\ 3\right)  dan turunan pertama fungsi f(x) adalah f’(x). maka hasil dari f’(x) adalah …

– 4 sin (2x + 3) cos (2x + 3)

4 sin (2x + 3) cos (2x + 3)

– 2 sin (2x + 3) cos (2x + 3)

2 sin (2x + 3) cos (2x + 3)

4 sin (2x + 3)3 cos (2x + 3)

5.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

Turunan pertama dari f(x) = x cotan 2x adalah …

2Cotan2x2xcosec22x2Co\tan2x–2x\operatorname{cosec}^22x

2tan2x2xcosec22x2\tan2x–2x\operatorname{cosec}^22x

2xCotan2xcosec22x2xCo\tan2x–\operatorname{cosec}^22x

Cotan2xxcosec22xCo\tan2x–x\operatorname{cosec}^22x

Cotan2x2xcosec22xCo\tan2x–2x\operatorname{cosec}^22x

6.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 F(x)=cos x5 + sin x,maka nilai dari f(π3)=F(x)=\frac{\cos\ x}{5\ +\ \sin\ x},maka\ nilai\ dari\ f’(\frac{\pi}{3})=…  

 8121\frac{-8}{121}  

 14121\frac{-14}{121}  

 14121\frac{14}{121}  

 17121\frac{17}{121}  

 18121\frac{18}{121}  

7.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

 F(x)=sin2 xx,maka nilai dari f(π3)=F(x)=\frac{\sin^2\ x}{x},maka\ nilai\ dari\ f’(\frac{\pi}{3})=…  

 2x sin x   cos x sin2 xx2\frac{2x\ \sin\ x\ \ -\ \cos\ x\ \sin^2\ x}{x^2}  

 2 sin x cos x  sin2 xx2\frac{2\ \sin\ x\ \cos\ x\ -\ \sin^2\ x}{x^2}  

 2x sin x cos x  sin2 xx2\frac{2x\ \sin\ x\ \cos\ x\ -\ \sin^2\ x}{x^2}  

 x sin2 x cos x  sin xx2\frac{x\ \sin^2\ x\ \cos\ x\ -\ \sin\ x}{x^2}  

 2x2x2 sin  x cos x\frac{2x^2}{x^2\ \sin\ \ x\ \cos\ x}  

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