General Mathematics Quiz

$$\frac{2x-3}{x-5}<\frac{4}{x}$$  

$$f(x)=\frac{x-1}{2x}$$  

$$\frac{5x}{x-2}$$  

$$x=\frac{3x}{x^2}$$  

$$\frac{2x}{3}=\frac{3}{x}$$  

$$f\left(x\right)=\frac{1}{x}$$  

$$2x^2<3x^2-5$$  

$$x+7>\frac{x-3}{x^2}$$  

The x’s and y’s are switched.

The x’s and y’s are divided by 2

The x’s and y’s are made negative.

The x’s and y’s are the same.

$$D:\left\{x∈R│x=-\frac{2}{3}\right\}$$  

$$D:\left\{x∈R│x\ne\frac{-2}{3}\right\}$$  

$$D:\left\{x∈R│x\ne\frac{2}{3}\right\}$$  

$$x:\left\{∈R│x=\frac{3}{2}\right\}$$  

$$f^+\left(x\right)$$  

$$f^1\left(x\right)$$  

$$f^2\left(x\right)$$  

$$f^{-1}\left(x\right)$$  

$$\left\{(2,-2),(1,-1),(0,0),(1,-3),(-2,5)\right\}$$  

$$\left\{(-2,2),(-1,1),(0,0),(1,3),(2,5)\right\}$$  

$$\left\{(2,-2),(1,-1),(0,0),(-3,1),(5,2)\right\}$$  

$$\left\{(-2,-2),(-1,-1),(0,0),(-1,-3),(-2,-5)\right\}$$  

$$D:\left\{x∈R\right\}$$  

$$D:\left\{x∈R│x=-3\right\}$$  

$$D:\left\{x∈R│x=10\right\}$$  

none of the choices

$$R:\left\{y∈R│y=-10\right\}$$  

$$R:\left\{y∈R\right\}$$  

$$R:\left\{y∈R|y>10\right\}$$  

$$R:\left\{y∈R|y<10\right\}$$  

$$2^4x=y$$  

$$3\left(5^{\left(x-2\right)}\right)=5y$$  

$$16y<128^{2x+5}$$  

$$y=0.5^{2x-1}$$  

8

3

2

1