Chapter 3 Test Review Honors Algebra 2

 $\$  Which of the following is equivalent to  $\left(-3a^3b^4\right)^3$  

Check all that apply!

•  $-9a^6b^7$  

•  $27a^9b^{12}$  

•  $-27a^9b^{12}$  

•  $\left(-3a^3b^4\right)\cdot\left(-3a^3b^4\right)\cdot\left(-3a^3b^4\right)$  

•  $-3\left(a^3b^4\right)^3$  

Tags

CCSS.HSA.APR.A.1

Find side m.

• 5

• 10

• $10\sqrt{3}$

• 15

• $5\sqrt{3}$

Tags

CCSS.HSG.SRT.C.8

 $\sqrt{8x^{12}y^5}$  

Simplify.

•  $2x^6y^2\sqrt{2y}$  

•  $2x^3y^3\sqrt{2y}$  

•  $4x^3y^2\sqrt{2y}$  

•  $2x^6y^2\sqrt{4y}$  

•  $2x^4y^2\sqrt{4y}$  

 $\left(64\right)^{-\frac{2}{3}}$  

Simplify.

• 216

•  $\frac{1}{16}$  

•  $\frac{1}{4}$  

• 4

•  $-\frac{1}{16}$  

 $\left(x+3\right)\left(2x^2-5x-8\right)$  

Multiply.

•  $2x^3-11x^2+23x-24$  

•  $2x^3-11x^2-23x-24$  

•  $2x^3+x^2-23x-24$  

•  $2x^3+x^2+23x-24$  

•  $2x^3-x^2+23x+24$  

Tags

CCSS.HSA.APR.A.1

 $-4x^3+64x$  

Factor completely.

•  $4x\left(-x^2+16\right)$  

•  $-4x\left(x^2-16\right)$  

•  $4\left(x+4\right)\left(x-4\right)$  

•  $-4\left(x+4\right)\left(x-4\right)$  

•  $-4x\left(x+4\right)\left(x-4\right)$  

Tags

CCSS.HSA.APR.C.4

 $5x^2-x-4$  

Which of the following is a factor of this trinomial?

• 5x+4

• x+1

• 5x-4

• x+4

• 4x+5

 $\frac{3x-2}{2-3x}$  

Which of the following is true regarding the expression above.
Check all that apply!

• It simplifies to 1

• It simplifies to - 1

• The denominator cannot equal  $\frac{2}{3}$  

• The denominator cannot equal  $\frac{3}{2}$  

• The domain is [- 1]

Tags

CCSS.HSA.APR.D.6

 $\frac{x^2-2x-15}{x^2-9}$  

Simplify.

•  $\frac{x+5}{x-3}$  

•  $\frac{x-5}{x+3}$  

•  $\frac{x-5}{x-3}$  

•  $\frac{x-5}{x+9}$  

•  $\frac{\left(x+3\right)\left(x-5\right)}{\left(x-3\right)\left(x+3\right)}$  

Tags

CCSS.HSA.APR.D.6

 $\frac{m^2-12m+32}{2m-8}\cdot\frac{2m^3-8m^2}{m-4}$  

Multiply.
Due to all the factoring, you have extended time with this problem.

•  $m^2\left(m-8\right)$  

•  $\frac{\left(m-6\right)\left(m+10\right)}{8m^2}$  

• 3

•  $\frac{10m}{9\left(m+10\right)}$  

•  $\frac{\left(m+6\right)\left(m-10\right)}{2\left(m-4\right)}$  

Tags

CCSS.HSA.APR.D.7