Search Header Logo

Perimeter and area of 2D shapes (Area and its Boundary) | Chapter Assessment | English | Grade 5

Authored by Tic Tac Learn

Mathematics

5th Grade

CCSS covered

Used 1+ times

Perimeter and area of 2D shapes (Area and its Boundary) | Chapter Assessment | English | Grade 5
AI

AI Actions

Add similar questions

Adjust reading levels

Convert to real-world scenario

Translate activity

More...

    Content View

    Student View

8 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The area of a square is equal to ______.

4 x side

2 x side

side x side

length + width

Answer explanation

The area of a square = side x side

Tags

CCSS.4.MD.A.3

CCSS.3.MD.C.7B

2.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Media Image

What is the area of this figure?

The distance between A and C

The length of its boundary

The space inside the figure

Length x Perimeter

Answer explanation

The space inside the figure is called area of the figure.

3.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The perimeter of a square shaped garden is 36 m. What is its area?

81 square metres

72 square metres

36 square metres

18 square metres

Answer explanation

Media Image

Perimeter of square shaped garden = 36 m We know that the perimeter of a square = 4 x length of one side So, 36 m = 4 x length of one side Length of one side = 36 ÷ 4 = 9 m Area of a square = side x side So area of the square shaped garden = 9 m x 9 m = 81 square metres.

Tags

CCSS.4.MD.A.3

CCSS.3.MD.C.7B

4.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Amita uses a 250 cm long piece of ribbon to make a border for a rectangular dupatta. If the length of the dupatta measures 90 cm, what is the width of the dupatta?

70 cm

160 cm

35 cm

80 cm

Answer explanation

Since a 250 cm long ribbon is used to make a border for the dupatta, the perimeter of the dupatta is 250 cm. Perimeter of a rectangle = length + width + length + width So, 250 cm = 90 cm + width + 90 cm + width 250 cm = 180 + 2 × width 250 cm - 180 cm = 2 x width 70 cm = 2 x width So width = 70 ÷ 2 = 35 cm

Tags

CCSS.3.MD.D.8

5.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

The length of a rectangular photograph is 14 cm and its area is 140 square cm. Find the width and the perimeter of the photograph.

Width = 10 cm Perimeter = 48 cm

Width = 10 cm Perimeter = 48 square cm

Width = 48 cm Perimeter = 10 cm

Width = 48 cm Perimeter = 10 square cm

Answer explanation

Length of the rectangular photograph is 14 cm. Area of the photograph = 140 square cm Area of photograph = length × width Or, 140 = 14 × width So, width = 140 ÷ 14 = 10 cm Perimeter of the photograph = length + width + length + width = 14 + 10 + 14 + 10 = 48 cm The width of the photograph is 10 cm, and the perimeter is 48 cm.

Tags

CCSS.4.MD.A.3

6.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

Mahira took 2 rounds of a rectangular park. The park had a length of 30 m and a width of 20 m. What distance did Mahira run?

600 m

1200 m

100 m

200 m

Answer explanation

The distance covered in running 1 round of the park = the perimeter of the park. Perimeter of park = 30 + 20 + 30 + 20 = 100 m Since Mahira took 2 rounds, the distance she ran = 2 × perimeter of park = 2 × 100 = 200 m

Tags

CCSS.4.MD.A.2

7.

MULTIPLE CHOICE QUESTION

30 sec • 1 pt

My rectangular room is 6 m long and 11 m wide. How much carpeting is needed to cover the entire floor?

17 square m

34 square m

33 square m

66 square m

Answer explanation

To find how much carpeting is needed, we must find the area of the room. Area of rectangular room = length × width = 6 × 11 = 66 square m Hence 66 square m of carpeting is needed to cover the entire room.

Tags

CCSS.4.MD.A.3

CCSS.3.MD.C.7B

Access all questions and much more by creating a free account

Create resources

Host any resource

Get auto-graded reports

Google

Continue with Google

Email

Continue with Email

Microsoft

Continue with Microsoft

or continue with

Facebook

Facebook

Apple

Apple

Others

Others

Already have an account?