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Solving Systems with Substitution

Authored by Karina Guarneros

Mathematics

9th Grade

CCSS covered

Used 13+ times

Solving Systems with Substitution
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20 questions

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1.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

The first step in solving using the substitution method is __________.

get x by itself

get y by itself

get either variable by itself in one equation

add the equations together

Tags

CCSS.HSA.REI.C.6

2.

MULTIPLE CHOICE QUESTION

5 mins • 1 pt

What does
"solution to a system of equations"
mean?

It's the point where both equations equal zero
It's the point where graphs of both equations cross the y-axis
It's the point that solves both equations at the same time
It's the point where graphs of both equations cross the x-axis

Tags

CCSS.HSA.REI.C.6

CCSS.HSA.REI.D.11

CCSS.HSA.REI.D.10

3.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Substitute y with x-1 to get 2x -3(x - 1) = -1

Substitute y with x-1 to get 2(x - 1) -3y = -1

Tags

CCSS.HSA.REI.A.1

4.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which variable can we substitute?

x = -3y - 17

2x + 3y = -7

Substitute x with -3y -17 to get 2(-3y - 17) + 3y= -7

Substitute x with -3y -17 to get 2x + 3(-3y - 17) = -7

Tags

CCSS.HSA.REI.C.6

CCSS.HSA.CED.A.2

5.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which equation is correctly using substitution for the system shown?

x = -3y - 8

x - 2y = -3

-3y -8 -2y = -3

x(-3y -8) -2y = -3

x -2(-3y-8) = -3

Tags

CCSS.HSA.REI.C.6

6.

MULTIPLE SELECT QUESTION

5 mins • 1 pt

How would you correctly substitute for this system?

y = 5x + 1

y = 3x + 13

Student answer y= 5(3x +13) +1

Replace the y in the second equation with 5x +1 and get 5x +1 = 3x +13

Replace the y in the first equation with 3x+ 13 and get 3x +13 = 5x +1

Replace the y in the first equation with 3x+ 13 and get y = 5(3x+13) +1

Replace the y in the second equation with 5x +1 and get y = 3(5x +1) +13

Tags

CCSS.HSA.REI.C.6

CCSS.HSA.REI.A.1

7.

MULTIPLE CHOICE QUESTION

3 mins • 1 pt

Which answer has a correct first step for this system:

3x + 3y = 3

y = 3x + 5

The variable is already isolated for y, so we've already solved the system.

The variable is already isolated for y, so we substitute it in the first equation 3(3x + 5) + 3y = 3 and then solve for x

The variable is already isolated for y, so we substitute it in the first equation 3x + 3(3x + 5) = 3 and then solve for x

Tags

CCSS.HSA.REI.C.6

CCSS.HSA.REI.A.1

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