Solving Quadratics

3x² = 12

• ± 2
• 2
• ± √12
• ± 4

Tags

CCSS.8.EE.A.2

x² + 4 = 68

• ± 8
• ± √8
• 8
• ± 64

Tags

CCSS.8.EE.A.2

7x² + 1 = 8

• ± 1
• ± 7
• ± √7
• ± 8

Tags

CCSS.8.EE.A.2

(x + 1) ² = 25

• ± 5
• 4  or  -6
• -4  or  6
• ± 4

16a² - 9 = 0

• a = ^-3/₄, ³/₄

• a = ^-4/₃, ⁴/₃

• a = ^-9/₁₆, ⁹/₁₆

• a = ^-16/₉, ¹⁶/₉

Tags

CCSS.8.EE.A.2

5b² - 4 = 41

• b = 9, b = -9

• b = 3, b = -3

• b = 8, b = -8

• no solutionb

Tags

CCSS.8.EE.A.2

5m² + 1 = 6

• m = 0

• m = 1 or -1

• m = √7

• m = 7/5 m = -7/5

Tags

CCSS.8.EE.A.2

Write the question and show all work.
(x-5)² = 25

• ±0
• ±10
• 10, 0
• -10, 0

Tags

CCSS.HSA-REI.B.4B

Solve for the values of x:
(x - 3)(x + 6) = 0

• { -3, -6 }
• { 3, -6 }
• { -3, -6 }
• { 3, 6 }

Tags

CCSS.HSA-REI.B.4B

What is the first step in solving 
(x + 2)(x - 3) = 0      ?

• Plug in zero for x
• Solve for x
• FOIL
• Set each binomial factor equal to zero

Tags

CCSS.HSA-REI.B.4B