Components and Tension

What is the normal force for a 10 kg sled on a ramp at 30 degrees above surface?

(Hint: need to find weight first, then normal is equivalent to one of the components)

• 85 N

• 100 N

• 120 N

• 65 N

Answer explanation

Weight =10*9.8=98N

Normal is opposite the Perpendicular component

cos30 * 98 = 84.87

Tags

NGSS.HS-PS2-1

NGSS.HS-PS2-4

What is the parallel component on a 20 kg suitcase sliding down a ramp at 30 degrees above surface?

• 10 N

• 57 N

• 98 N

• 196 N

Answer explanation

Need weight first. W=20*9.8=196N

parallel component

sin30 * 196 N=98 N

Tags

NGSS.HS-PS2-1

NGSS.HS-PS2-4

Which of the following is the best expression for the Normal Force?

• F_N = mg cos(ϴ)

• F_N = mg sin(ϴ)

• F_N = mg sin(180-ϴ)

• F_N = mg cos(90-ϴ)

Tags

NGSS.HS-PS2-1

A late traveler rushes to catch a plane, pulling a suitcase with a force directed 30.0° above the horizontal. If the horizontal component of the force on the suitcase is 60.6 N, what is the force exerted on the handle?

(Hint: a new twist on our regular component problems, they give you component, can you find hypotenuse?)

• 96

• 53

• 70.

• 65

Answer explanation

cos30=60.6/hyp

hyp = 60.6/cos30

hyp or force on handle = 69.97 N

Tags

NGSS.HS-PS2-1

How would you find the magnitude of a resultant vector that has an x component of 8 N and a y component of 6 N?

A 50 N tension force exists on wires holding up the clown portrait. What is the horizontal component of the force?

• 25 N

• 33 N

• 43 N

• 48 N

Answer explanation

horizontal would be adjacent to angle 30 degrees so you need the cosine component

Tags

NGSS.HS-PS2-1

A 50 N tension force exists on wires holding up the clown portrait. What is the vertical component of the force?

• 25 N

• 33 N

• 43 N

• 48 N

Answer explanation

vertical would be opposite t to angle 30 degrees so you need the sine component

Tags

NGSS.HS-PS2-1

A 50 N tension force exists on wires holding up the clown portrait. Carefully consider the 2 sides have vertical components holding the picture in equilibrium. How much do you think the portrait must weigh?

• 25 N

• 86 N

• 50 N

• 100 N

Answer explanation

2 wires (one on each side) are pulling UP with 25 N each, so the portrait much pull DOWN with the exact same amount, which = 50 N

Tags

NGSS.HS-PS2-1

What is the net force?

• 40 N left
• 0 N Balalnced
• 400 N right
• 40 N right

Tags

NGSS.HS-PS2-1

What is the net force?

• 400 N Up
• 400 N Down
• - 400 N Down
• 800 N Down

Tags

NGSS.HS-PS2-1