10학년 나머지정리와 인수분해 정리(4/15)

$$-1$$  

$$0$$  

$$1$$  

$$2$$  

$$\left(x-1\right)$$  로 나눈 나머지 5

$$x$$  로 나눈 나머지 5

$$\left(x+2\right)$$  로 나눈 나머지 55

$$\left(x+\frac{1}{2}\right)$$  로 나눈 나머지 11

$$\left(2x+1\right)$$  로 나눈 나머지 $$\frac{5}{8}$$  

$$\left(3x-2\right)$$  로 나눈 나머지 $$\frac{5}{27}$$  

$$\left(x-1\right)$$  로 나눈 나머지 -1

$$x$$  로 나눈 나머지 2

-1

0

1

2

-2

-1

1

2

1

3

5

7

$$64x^3+48x^2+12x+1=\left(4x+1\right)^3$$  

$$x^3-6x^2y+12xy^2-8y^3=\left(x-2y\right)^3$$  

$$x^3-64y^3=\left(x-4y\right)\left(x^2-4xy+16y^2\right)$$  

$$x^3+27=\left(x+3\right)\left(x^2-3x+9\right)$$  

$$x\left(x-1\right)\left(x^2-3x+5\right)$$  

$$\left(x-1\right)\left(x+2\right)\left(x^2-3x+5\right)$$  

$$\left(x-1\right)\left(x-2\right)\left(x^2-3x+5\right)$$  

$$\left(x-1\right)\left(x+2\right)\left(x^2-3x+5\right)$$  

$$\left(x^2+1\right)^2$$  

$$\left(x^2+1\right)\left(x^2-1\right)$$  

$$\left(x^2+x+1\right)\left(x^2-x-1\right)$$  

$$\left(x^2+x+1\right)\left(x^2-x+1\right)$$  

$$\left(x-2\right)\left(x-3\right)\left(x-1\right)$$  

$$\left(x-1\right)\left(2x^2-x+6\right)$$  

$$\left(x+1\right)\left(2x^2-x-6\right)$$  

$$\left(x-1\right)\left(2x^2+x+6\right)$$