Algebra II Unit 8 Assessment Review Part A

Solve!

• x = 2
• x = 6
• x = 4
• x = 8

Solve by cross-multiplying.

• x = 2
• No Solution
• x = -10
• x = 10

Solve the equation for x.

• 6
• 12
• 0
• 3

Solve 

• x = 0 , 4
• x = 1 , 3
• x = -4 , 0
• x = 5 , 2

Solve by cross multiplying

 $\frac{x}{2x+7}=\frac{x-5}{x-1}$  

• x = -1 x = 2

• x = -1, x = 7

• x = -1, x = 3

• x = -5, x = 2

• x = -5, x = 7

• {-10, 3}

• {10, -3}

• {6, -5}

• {-6, 5}

Solve for r

• 5
• - 5, 4
• - 5
• 5, 4

Solve $\frac{x-2}{3x}=\frac{1}{3x}+2$  

• 0

•  $-\frac{3}{5}$  

• -2

•  $-\frac{1}{5}$  

Solve!

• x = 36/7
• x = 6
• x = 44/7
• x = 0

Solve for x:
 $\frac{x}{x+2}+x=\frac{5x+8}{x+2}$  

• 2

• 4

• 6

• 8