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Null and Alternative Hypothesis

Authored by Jose Maningas

Mathematics

11th Grade - Professional Development

Used 14+ times

Null and Alternative Hypothesis
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5 questions

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1.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the null and alternative hypothesis.

The standard deviation of the sale price of a bike is no

more than $225.

H0: σ=225H_0:\ \sigma=225  

H1: σ<225H_1:\ \sigma<225  

H0: σ≠225H_0:\ \sigma\ne225   H1: σ<225H_1:\ \sigma<225  

H0: σ≠225H_0:\ \sigma\ne225   H1: σ>225H_1:\ \sigma>225  

H0: σ=225H_0:\ \sigma=225   H1: σ>225H_1:\ \sigma>225  

2.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the null and alternative hypothesis.

A museum claims that its mean daily attendance is at least 300 people.

H0: μ=300H_0:\ \mu=300  

H1: μ>300H_1:\ \mu>300  

H0: μ≠300H_0:\ \mu\ne300   H1: μ>300H_1:\ \mu>300  

H0: μ≠300H_0:\ \mu\ne300   H1: μ<300H_1:\ \mu<300  

H0: μ=300H_0:\ \mu=300   H1: μ<300H_1:\ \mu<300  

3.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the null and alternative hypothesis.

A microwave manufacturer claims that the mean life of the thermostat for a certain model of microwave is more than 4 years.

H0: μ=4H_0:\ \mu=4  

H1: μ>4H_1:\ \mu>4  

H0: μ=4H_0:\ \mu=4   H1: μ<4H_1:\ \mu<4  

H0: μ≠4H_0:\ \mu\ne4   H1: μ>4H_1:\ \mu>4  

H0: μ≠4H_0:\ \mu\ne4   H1: μ<4H_1:\ \mu<4  

4.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the null and alternative hypothesis.

As stated by a courier company’s dispatch department, the number of delivery errors per million consignments has a mean that is less than 2.

H0: μ=2H_0:\ \mu=2  

H1: μ<2H_1:\ \mu<2  

H0: μ=2H_0:\ \mu=2   H1: μ>2H_1:\ \mu>2  

H0: μ≠2H_0:\ \mu\ne2   H1: μ<2H_1:\ \mu<2  

H0: μ≠2H_0:\ \mu\ne2   H1: μ>2H_1:\ \mu>2  

5.

MULTIPLE CHOICE QUESTION

45 sec • 1 pt

Find the null and alternative hypothesis.

According to a recent survey, 73% of college students did not use student loans to pay for college.

H0: μ=73H_0:\ \mu=73  

H1: μ≠73H_1:\ \mu\ne73  

H0: μ=73H_0:\ \mu=73   H1: μ>73H_1:\ \mu>73  

H0: μ=73H_0:\ \mu=73   H1: μ<73H_1:\ \mu<73  

H0: μ≠73H_0:\ \mu\ne73   H1: μ=73H_1:\ \mu=73  

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