
Math Puzzles and Problems
Authored by Arsh MD
Mathematics
9th Grade
CCSS covered
Used 18+ times

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10 questions
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1.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the missing number.
22
25
0
24
Answer explanation
In the top triangle, 4 + 6 + 12 = 22
In the second row, the second triangle has a sum of three numbers; 8 + 3 + 11 = 22
Thus, the missing number in the puzzle is:
7 + 5 + 13 = 25
Tags
CCSS.7.EE.B.3
2.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
What is the missing number?
9
3
4
6
Answer explanation
The numbers in the second row (from the bottom) are the difference of the corresponding two numbers in the bottom row.
That means, 6 = 8 – 2
1 = 3 – 2
7 – 3 =?
Similarly,
6 – 1 = 5, ? – 1 = 3
And
5 – 3 = 1
From the above, we can say that the missing value is equal to 4.
Tags
CCSS.1.OA.A.1
3.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the odd one out.
740, 185, 37, 407, 1369, 111, 78
185
111
37
78
Answer explanation
All the other numbers are divisible by 37 except 78.
Tags
CCSS.4.OA.B.4
4.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Rationalise.
0
Tags
CCSS.HSN.RN.A.2
5.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Simplify (√5-√2)(√5+√2)
21
0
3
Answer explanation
Using the identity, (a+b) (a-b) = a2 - b2
(√5-√2)(√5+√2) = (√52-√22) = 5-2 = 3
Tags
CCSS.HSN.RN.A.2
6.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the value of m, if x + 4 is a factor of the polynomial x2 + 3x + m.
-4
4
0
Answer explanation
Let p(x) = x2 + 3x + mSince (x + 4) or (x – (-4)} is a factor of p(x).∴ p(-4) = 0⇒ (-4)2 + 3(-4) + m = 0⇒ 16 – 12 + m = 0⇒ m = -4
Tags
CCSS.HSA.APR.B.2
7.
MULTIPLE CHOICE QUESTION
1 min • 1 pt
Find the remainder when x3+ x2 + x + 1 is divided by x – 12 using remainder theorem.
0
Answer explanation
Let p(x) = x3+ x2 + x + 1 and q(x) = x – 12Here, p(x) is divided by q(x)∴ By using remainder theorem, we have.
Tags
CCSS.HSA.APR.B.2
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