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Math Puzzles and Problems

Authored by Arsh MD

Mathematics

9th Grade

CCSS covered

Used 18+ times

Math Puzzles and Problems
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10 questions

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1.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Find the missing number.

22

25

0

24

Answer explanation

Media Image

In the top triangle, 4 + 6 + 12 = 22

In the second row, the second triangle has a sum of three numbers; 8 + 3 + 11 = 22

Thus, the missing number in the puzzle is:

7 + 5 + 13 = 25

Tags

CCSS.7.EE.B.3

2.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

What is the missing number?

9

3

4

6

Answer explanation

The numbers in the second row (from the bottom) are the difference of the corresponding two numbers in the bottom row.

That means, 6 = 8 – 2

1 = 3 – 2

7 – 3 =? 

Similarly,

6 – 1 = 5, ? – 1 = 3

And

5 – 3 = 1

From the above, we can say that the missing value is equal to 4.

Tags

CCSS.1.OA.A.1

3.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the odd one out.

740, 185, 37, 407, 1369, 111, 78

185

111

37

78

Answer explanation

All the other numbers are divisible by 37 except 78.

Tags

CCSS.4.OA.B.4

4.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Media Image

Rationalise.

Media Image
Media Image

0

Tags

CCSS.HSN.RN.A.2

5.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Simplify (√5-√2)(√5+√2)

21

0

3

Answer explanation

Using the identity, (a+b) (a-b) = a2 - b2

(√5-√2)(√5+√2) = (√52-√22) = 5-2 = 3

Tags

CCSS.HSN.RN.A.2

6.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the value of m, if x + 4 is a factor of the polynomial x2 + 3x + m.

-4

4

0

Answer explanation

Let p(x) = x2 + 3x + mSince (x + 4) or (x – (-4)} is a factor of p(x).∴ p(-4) = 0⇒ (-4)2 + 3(-4) + m = 0⇒ 16 – 12 + m = 0⇒ m = -4

Tags

CCSS.HSA.APR.B.2

7.

MULTIPLE CHOICE QUESTION

1 min • 1 pt

Find the remainder when x3+ x2 + x + 1 is divided by x – 12 using remainder theorem.

0

Answer explanation

Media Image

Let p(x) = x3+ x2 + x + 1 and q(x) = x – 12Here, p(x) is divided by q(x)∴ By using remainder theorem, we have.

Tags

CCSS.HSA.APR.B.2

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