Factoring Polynomials

x⁴ - 4x² - 45

• (x² - 5)(x - 3)(x + 3)
• (x² + 45)(x + 1)(x - 1)
• (x² + 5)(x - 3)(x + 3)
• (x² + 3)(x - 5)(x + 3)

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

x⁴ - 48x² - 49

• (x² - 7)(x - 7)(x + 1)
• (x² + 49)(x² + 1)
• (x - 7)(x - 7)(x² + 1)
• (x + 7)(x - 7)(x² + 1)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.SSE.A.2

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Tags

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

Tags

CCSS.HSA.SSE.A.2

• x⁴(x² - 5x - 24)
• (x - 8)(x + 3)
• x⁴(x - 8)(x + 3)
• (x³ - 8)(x³ +3)

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

CCSS.HSA.SSE.B.3

FInd all zeros for the polynomial
f(x) = x⁴+8x²-9

• -1, ⅓, ±3i
• ½, -1, ±3i
• 1, -1, ±i√11
• 1, -1, ±3i

Tags

CCSS.HSA.APR.B.3

How many zeros does the polynomial function
 P(x) = 3x⁴+4x-8 have?

• 1
• 2
• 3
• 4

Tags

CCSS.HSA.APR.B.3

Solve x⁴ - 256 = 0

• x = 4, x = - 4
• x = 4, x = 4i
• x = 4, x -4, x = 4i
• x = 4, x -4, x = 4i,         x = -4i

Tags

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2

CCSS.HSN.CN.A.1

CCSS.HSN.CN.A.2

Solve the following equation. x⁴ + 4x³ + 3x² = 0

• x = 0, x = 3, x = 1

• x = -3, x = -1

• x = 3, x = 1

• x = 0, x = -3, x = -1

Tags

CCSS.HSA.APR.A.1

CCSS.HSA.APR.B.2

CCSS.HSA.APR.B.3

CCSS.HSA.SSE.A.2