VCE Physics - Diffraction Patterns 1 - waves and particles

VCE Physics - Diffraction Patterns 1 - waves and particles

12th Grade

12 Qs

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VCE Physics - Diffraction Patterns 1 - waves and particles

VCE Physics - Diffraction Patterns 1 - waves and particles

Assessment

Quiz

Physics

12th Grade

Hard

Created by

Craig Anderson

Used 1+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Which one of the following is closest to the de Broglie wavelength of a 663 kg motor car moving at 10 m s−1?

VCAA 2021

10−37 m

10−36 m

10−35 m

10−34 m

Answer explanation

Use p = Use p=h/λ

       λ = h/p

= h/mv

= 6.63 × 10−34 /(663 × 10)

       λ = 1.00 × 10-37 m

2.

MULTIPLE SELECT QUESTION

1 min • 5 pts

Media Image

When a beam of X-rays of a single wavelength passes through a metal foil, a pattern of rings is detected by photographic film.

How do the X-rays produce this pattern of rings?

(Select two options)

VCAA 2000

the ring pattern was an interference/diffraction pattern formed by the X-rays passing through the metal

the rings themselves represented positions of destructive interference

the rings themselves represented positions of constructive interference

the pattern occurs because the wavelength of the X-rays is half that of the atomic spacing of the metal crystal.

the interference pattern occurs because the metal foil atoms block transverse waves in most directions

3.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

A parallel beam of red light is incident on a single slit. A photographic film placed several metre away records the resultant diffraction pattern. The diagram indicates the intensity of light recorded on the film.

The diffraction pattern can be explained if one assumes that

VCAA 1971

the two edges of the slit are acting as two point sources in phase

the slit is acting as a single point source.

the slit is acting as two point sources half a cycle out of phase

the slit is acting as a row of point sources in phase

Answer explanation

The local minima are from destructive interference between two pairs of points. To determine their position, we model the slit as a series of adjacent point sources.

4.

MULTIPLE SELECT QUESTION

1 min • 5 pts

Media Image

When light of single wavelength passes through two close, narrow slits a pattern of light and dark bands is observed on a screen that is about 2 metres from the slits. The experimental arrangement is illustrated

Select two options that explain whether the particle model or the wave model for light best explains the observations of this experiment.

VCAA 1997

Waves from the two slits will interfere with each other to form the dark and light bands. Light bands are constructive interference.

Photons of light that are in phase will pass through the slits and collide to form dark bands

Bright bands are formed when the path difference from each slit is a whole multiple of the wavelength

Inteference is evidence of the particle nature of light

Answer explanation

This interference pattern is best explained from the wave model. Waves from the two point sources (the slits) will interfere with each other at the screen. You will get bands of constructive and destructive interference. A path difference of λ/2, 3λ/2, 5λ/2 etc. will produce nodal lines. (A dark band is due to destructive interference). The bright central band will always be a region where constructive interference occurs

5.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

The figure shows both an X-ray diffraction pattern (the upper half of the figure), and a diffraction pattern obtained using electrons (the lower half of the figure). Both were obtained with an aluminium foil.

The X-ray photons had an energy of 2.38 × 10-16 J, and a momentum of 7.94 × 10-25 kg m s-1.

What was the wavelength of the X-rays used in this experiment?

VCAA 1995

1.2 x 109 m

5.2 x 1010 m

8.4 × 10-10 nm

8.4 × 10-10 m

Answer explanation

From λ = h/p

We get

 λ = h/p

= (6.63x10-34)/(7.94x10-25)

= 8.4 × 10-10 m

6.

MULTIPLE SELECT QUESTION

1 min • 5 pts

Media Image

The figure shows both an X-ray diffraction pattern (the upper half of the figure), and a diffraction pattern obtained using electrons (the lower half of the figure). Both were obtained with an aluminium foil.

The electron and X-ray diffraction patterns have the same spacing between rings. Did the electrons which produced the pattern have the same energy as the X-ray photons used, or the same momentum as the X-ray photons? (select two options)

VCAA 1995

The wavelength is the same, so the momentum will be the same

The wavelength is the same, so the energy will be the same

The same spacing means the energy is the same

The same spacing means the wavelength is the same

Answer explanation

The same diffraction pattern implies that the wavelength is the same.

The same wavelength implies that the momentum is the same.

7.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

The diffraction patterns for X-rays and electrons through thin polycrystalline aluminium foil have been combined in the diagram, which shows an electron diffraction pattern on the left and an X-ray diffraction pattern on the right. The images are to the same scale.

The X-rays have a photon energy of 8000 eV.

Calculate the wavelength of the electrons in nanometres

2018 VCAA

0.155 nm

1.55 x 10-10 m

2.48 x 10-20 nm

0.31 nm

Answer explanation

The X-rays have photons with energy of 8000 eV,

Use E =  to find the wavelength of the X-rays. The electrons will have the same wavelength as they have the same diffraction pattern.

For an X-ray, E =  hc/λ

 λ =  hc/E

=  4.14 x 10-15 x 3 x 108 /8000

= 1.55 × 10-10 m

λ = 0.155 nm

The answer in nm as requested.

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