VCE Physics - Random Exam Revision 4

VCE Physics - Random Exam Revision 4

12th Grade

12 Qs

quiz-placeholder

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VCE Physics - Random Exam Revision 4

VCE Physics - Random Exam Revision 4

Assessment

Quiz

Physics

12th Grade

Hard

Created by

Craig Anderson

Used 7+ times

FREE Resource

12 questions

Show all answers

1.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Media Image

Two identical bar magnets of the same magnetic field strength are arranged at right angles to each other and at the same distance from point P, as shown.

At point P on the figure, draw an arrow indicating the direction of the combined magnetic field of the two bar magnets.

VCAA 2021

Media Image
Media Image
Media Image
Media Image

Answer explanation

The direction of the field is given by the sum of the fields from the horizontal magnet (to the right) and from the vertical magnet (down). The two components have the same size so the angle needed to be 450. Make sure that you arrow touches point P.

2.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Media Image

The figure below shows the source of a magnetic field.

Which magnetic field pattern it produce?

VCAA 2005 Modified

Media Image
Media Image
Media Image

3.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Media Image

The figure below shows the source of a magnetic field.

Which magnetic field pattern it produce?

VCAA 2005 Modified

Media Image
Media Image
Media Image

4.

MULTIPLE CHOICE QUESTION

30 sec • 5 pts

Media Image

The figure below shows the source of a magnetic field.

Which magnetic field pattern it produce?

VCAA 2005 Modified

Media Image
Media Image
Media Image

5.

MULTIPLE CHOICE QUESTION

3 mins • 5 pts

Media Image

The figure below shows a small ball of mass 1.8 kg travelling in a horizontal circular path at a constant speed while suspended from the ceiling by a 0.75 m long string.

Calculate the speed of the ball.

VCAA 2020

1.2 ms-1

1.4 ms-1

1.8 ms-1

3.1 ms-1

Answer explanation

In the vertical direction

T cos 250 = mg (1)

In the horizontal

T sin 250 =   mv2/r       (2)

 

Dividing (2) by (1) gives

tan 250 = v2/rg

       v2 = rgtan 250

 

You need to find ‘r’.

r = 0.75 × sin 250

r = 0.317 m

v = sqrt (0.317 x 9.8 x tan 250)

v = 1.2 m s-1

6.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Media Image

A rubber stopper of mass m is whirled in a horizontal circle of radius r.

An experiment is performed to investigate the relationship between m, r, the speed of the stopper v, and the centripetal force, F, acting on the stopper.

The centripetal force acting on the stopper can be measured during the experiment by:

VCAA 1976

finding the mass of the stopper and multiplying by g, the acceleration due to gravity.

finding the mass of the stopper and multiplying by v2/r

multiplying the weight, mg, of the stopper by v2/r

counting the number of iron washers on the end of the string.

Answer explanation

The net force is always given as Fnet.

       Fnet = mv2/r

7.

MULTIPLE CHOICE QUESTION

1 min • 5 pts

Which one of the following statements about systematic and random errors is correct?

Random errors can be reduced by repeated readings.

Both random and systematic errors can be reduced by repeated readings

Systematic errors can be reduced by repeated readings.

Neither systematic nor random errors can be reduced by repeated readings

Answer explanation

The official answer was "...repeated readings", although it hs been contested that this may not reduce the random errors, but provide a greater range of random errors.

increasing the number of trials can reduce the effect of the random errors.

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