If AB//CD, Find the value of x, y and z from given figure. click,which are correct answer?

Solution: In triangle EFG, <EFG+<FGE+<GEF=180°[Sum of three angles of triangle] or,x°+2x-5°+2x+5°=180° or,5x°=180° or,x°=180°/5 x°=36° Continue

<AEF=<EFG[alternate angle] or,Z=2x-5 Or, z=2×36-5 or,z=72-5 or,z=67°

<BEG=<EGF[alternate angle] or,y= 2x+5° or,y=2×36+5 or,y=72+5 or,y=77

<BEG=<EGF[alternate angle] or,y= 2x+5° or,y=2×36+5 or,y=72+5 or,y=87°

Find the value of a, x ,y and z. Click below Answers ,Which are correct.?

Solution: MN //PQ ,CD is transversal line. □ <EFG=<CEN [Corresponding angle] Z°=40° □<EGF=<QGV[Vertically Opposite Angle] a°=50°

In Triangle EFG <EFG+<EGF+<GEF=180°[Sum of three angles of triangle] Z°+a°+y°=180° or,40°+50°+y=180° or,90°+y°=180° or,y°=180°-90° y°=90°

<UEC=<FEG[Vertically Opposite Angle] or, x°=y° x°=90°

<UEC=<FEG[Vertically Opposite Angle] or, x°=y° x°=50°

Find the value of x, y and z. Which are correct answers?click

Solution:]] AB //CD ,EB is a transversal line. <CGE=<ABG [corresponding angle] z°=38°

<CGB+<ABG=180° [Co-interior angle] or y°+38°=180° or,y°=180°-38° y°=142°

EB//FD. CD is transversal line. <GDF=<CGE[Corresponding angle] or,x°=z° x°=38°

CGB+<ABG=180° [Co-interior angle] or y°+38°=180° or,y°=180°-38° y°=152°

Find the value of a,x,y and z. Which are correct answers? Click.

AB//CD is given, a parallel line MN is drawn between them. So AB // MN // CD <EUA+<EUB=180°[Supplementary angle's sum] or, a°+50°=180° or,a°=180°-50° or,a=130°

□ <DVF=<CVT[Vertically Opposite Angle] Y°=45° <FVC+<DVF=180°[Supplementary angle's sum] or, z°+y°=180° z°+45°=180° or,z°=180°-45° z°=135°

AB//MN • <UTN=<EUB[corresponding angle] <UTN=50° • <NTV=<TVC[alternate angle] <NTV=45° • < UTV=<UTN+<VTN[whole part of Axioms] or,x°=50°+45° x°=95°

<EUA+<EUB=180°[Supplementary angle's sum] or, a°+50°=180° or,a°=180°-50° or,a=120°

Find the value of a ,x ,y and z from given figure alone side. Which answers are correct?click

Solution:AB//CD//EF and GI is transversal line. <DJK=FKI[corresponding angle] x°=75° <BIJ=<FKI [corresponding angle] a°=75°

<JKF+<IKF=190°[Supplementary angle's sum] or, z°+75°=180° or,z°=180°-75° or,z°=105° <IJD=<JKF[corresponding angle] or, y°=z° or,y°=105°

<BIJ=<DJK=<FKI[corresponding angle] a°=x°=75° <IJD=<JKF[corresponding angle] or, y°=z° or,y°=105°

<JKF+<IKF=190°[Supplementary angle's sum] or, z°+75°=180° or,z°=180°-75° or,z°=15°

Find the value of a, x ,y and z. Which are correct answers?

Solution: <AIJ=<EIK [Vertically Opposite Angle. ] x°=115° <FJC=<JIA[corresponding angle] or,y°=x° y°=115°

<IKL=<GKB[vertically opposite angle] z°=58° <KLD= <LkI[alternate angle] or,a°=z° a°=58°

<IKL=<GKB[vertically opposite angle] z°=58° <KLD= <GKB[corresponding angle] a°=58

<IKL=<GKB[vertically opposite angle] z°=48° <KLD= <LkI[alternate angle] or,a°=z° a°=48°

Find the value of x, y and z . Which are correct answers?

Solution: triangle CDE is isosceles triangle. <CDE=<CED[base angle of isosceles triangle] y°=x° <ACD=<CED+<CDE[Exterior angle of a triangle equal to sum of its opposite non adjacent interior angles ] 120°=x°+y° or, 120°=x°+x° or,2x°=120° x°=120°/2 : . x°=60° Continue

Y°=X °=60° <CED+<DEB=180°[adjacent angle formed on Straight line. or, Z °+ X°=180° or, Z°+60°=180° Z°=180°-60° Z°=120°

<CED+<DEB=180°[adjacent angle formed on Straight line. or, Z °+ X°=180° or, Z°+60°=180° or,Z°=180°+60° Z°=240°

<ACD=<CED+<CDE[Exterior angle of a triangle equal to sum of its opposite non adjacent interior angles ] 120°=x°+y° or, 120°=x°+x° or,3x°=120° x°=120°/3 : . x°=40°

Find the value of x and y. Which are correct? Click.

Solution: <AGF+<IGF=180°[adjacent angle formed on Straight line] or, 60° + x°= 180° or,x=180°-60° x=120°

<GHi+<HIG=<FGI[Exterior angle of a triangle is equal to sum of opposite non adjacent interior angles ] or,45°+y°=x° or,y°=x°-45° or,y°=120°-45° y°=75°

Solution: <AGF+<IGF=170°[adjacent angle formed on Straight line] or, 60° + x°= 170° or,x=170°-60° x=110°

<GHi+<HIG=<FGI[Exterior angle of a triangle is equal to sum of opposite non adjacent interior angles ] or,45°+y°=x° or,y°=x°-45° or,y°=120°-45° y°=85°

Find the value of (i) p b - c × p a - b × p c - a (ii) x y- x × x x- y × x z - x (iii)x r- p × x p- q × x r - p

(i)Solution: p b - c x p a - b x p c - a =p b - c +a-b+ c-a =p o =1

(ii) Solution: x y- x × x x- y ×x z - x = x y- x+ x- y+ z- x = $$x^o$$ =1

(iii)Solution: x r- p × x p- q × x r - p =x r- p +p -q + r-p = $$x^o$$ =1

(iii)Solution: x r- p × x p- q × x r - p =x r- p +p -q + r-p = $$x^o$$ =0

Q)find the area of given rectangle. Q) if l= (5a-b) m,b=(2a+b)m find area of rectangle.

Solution: A= lXb = (5a-b) (2a+b) =5a(2a+b)-b(2a+b) $$10a^2+5ab-2ab-b^2$$ = $$10a^2+3ab-b^2$$

Solution: A= lXb = (5a-b) (2a+b) =5a(2a+b)+b(2a+b) $$10a^2+5ab+2ab+b^2$$ = $$10a^2+3ab+b^2$$

class 7 math quiz

Quiz

•

Mathematics

•

7th Grade

•

Practice Problem

•

Hard

Dor Bahadur Aryal

Used 55+ times

FREE Resource

36 questions

Show all answers

MULTIPLE SELECT QUESTION

1 min • 5 pts

Figure is scalene triangle ABC.

It's angles sum equal to 180°.

It's made by using pencil compass.

It's made by using set Square and protactor.

MULTIPLE SELECT QUESTION

2 mins • 5 pts

Click if it's a correct answer.

क) Solution:

<AOB+<AOC=180°[° .° Being Supplementary angle's sum]

or,2x+3x+45°=180°

or,5x+45°=180°

or,5x=180°-45°

or,5x=135°

or,x=135°/5

x=27°

Click if it's a correct answer.

क) Solution:

<AOB+<AOC=180°[° .° Being Supplementary angle's sum]

or,2x+3x+45°=180°

or,5x+45°=180°

or,5x=180°-45°

or,5x=135°

or,x=135°/5

x=17°

Click if it's a correct answer.

ग) Solution:<AOD +<AOB+<BOC+<COD=360°[Sum of angles formed on a point=360°]

or,7x+50°+3x+110°=360°

or,10x+160°=360°

or, 10x=360°-160°

or,10x=200°

or,x=200°/10

x=20°

Click if it's a correct answer.

घ) Solution:

Interior<AOB+ exterior <AOB=360°

or,80°+7y=360°

or,7y=360°-80°

or,7y=280°

or,y=280°/7

y=50°

Answer explanation

घ) Solution:
Interior<AOB+ exterior <AOB=360°
or,80°+7y=360°
or,7y=360°-80°
or,7y=280°
or,y=280°/7
y=40°
क) Solution:
<AOB+<AOC=180°[° .° Being Supplementary angle's sum]
or,2x+3x+45°=180°
or,5x+45°=180°
or,5x=180°-45°
or,5x=135°
or,x=135°/5
x=27°

MULTIPLE SELECT QUESTION

45 sec • 5 pts

Find the value of x , y and a from given figure:
(answer are given below click which are correct.)

( II) <AEC+<AED=180°[Sum of angle formed on straight line.]

Or,3a+y=180°

or, 3×40°+y=180°

or 120°+y=180°

or,y=180°-120°

y=60°

(III) <BEC = <AED [Vertically Opposite Angle ]

or, x = y

or, x= 60°

[So,a=40°,y=60° and x=60°]

(III) <BEC = <AED [Vertically Opposite Angle ]

or, x = y

or, x= 60°

MULTIPLE SELECT QUESTION

45 sec • 5 pts

Line AB and DC are Perpendicular line.

Line ADand BC are Perpendicular line.

Line AD and AB are Parallel line.

Line BC and AB are Parallel line.

Line AD and AB are Parallel line.

Line BC and CD are Parallel line.

Line AB and DC are Parallel line.

Line AD and BC are Parallel line.

Line AD and AB are Perpendicular line.

Line BC and AB are Perpendicular line.

Line AD and AB are Perpendicular line.

Line BC and CD are Perpendicular line.

MULTIPLE SELECT QUESTION

45 sec • 5 pts

See figure,Click if answer is correct.

ख) Solution:

<POR+<ROQ=180°[° .° Being Supplementary

angle's sum]

or,70°+2y+10°=180°

or,2y+80°=180°

or,2y=180°-80°

or,2y=100°

or,y=100°/2

y=50°

Continue

ख) Solution:( middle part)

Again,<POR=<QOS [Being vertically

opposite angle]

or,70°=b

b=70°

Continue

ख) Solution:(last part)

Now,<POS=<ROQ [Being vertically

opposite angle]

x=2y+10°

or,x=2×50°+10°

or,x=100°+10°

x=110°

ख) Solution:

<POR+<ROQ=180°[° .° Being Supplementary

angle's sum]

or,70°+2y+10°=180°

or,2y+80°=180°

or,2y=180°-80°

or,2y=100°

or,y=100°/2

y=60°

Again,<POR=<QOS [Being vertically

opposite angle]

or,70°=b

b=75°

Now,<POS=<ROQ [Being vertically

opposite angle]

x=2y+10°

or,x=2×50°+10°

or,x=100°+10°

x=120°

Answer explanation

ख) Solution:
<POR+<ROQ=180°[° .° Being Supplementary
angle's sum]
or,70°+2y+10°=180°
or,2y+80°=180°
or,2y=180°-80°
or,2y=100°
or,y=100°/2
y=50°
Again,<POR=<QOS [Being vertically
opposite angle]
or,70°=b
b=70°
Now,<POS=<ROQ [Being vertically
opposite angle]
x=2y+10°
or,x=2×50°+10°
or,x=100°+10°
x=110°

MULTIPLE SELECT QUESTION

45 sec • 5 pts

Click if given below statement are correct .

In letter X and L

AD and BC are intersecting line.

AD and BC are not parallel line.

AC and CZ are perpendicular line.

In letter X and L

AD and BC are parallel line.

AD and BC are not intersecting line.

AC and CZ are not perpendicular

MULTIPLE SELECT QUESTION

2 mins • 5 pts

Click if Answers are correct.

क) उत्तर,

यहा,त्रिभुज ABC को भुजा (AB )=12 cm

त्रिभुज ABC को भुजा (BC)=5 cm

त्रिभुज ABC को भुजा (AC )=13cm

त्रिभुज ABC को परिमिति (perimeter)=?

अब, P =AB+BC+AC

=12cm+5cm+13cm

=30cm

Click if Answers are correct.

ख) उत्तर,

यहा,त्रिभुज XYZको भुजा (XY)=3 cm

त्रिभुज XYZको भुजा (YZ)=4 cm

त्रिभुज XYZ को भुजा (XZ)=3.9cm

त्रिभुज XYZ को परिमिति (perimeter)=?

अब, P =XY+YZ+ZX

=3cm+4cm+3.9cm

=10.9cm

Click if Answers are correct.

ग) उत्तर,

यहा,त्रिभुज PQR को भुजा (PQ )=5.5 cm

त्रिभुज PQR को भुजा (QR)=8.5 cm

त्रिभुज PQR को भुजा (PR )=5cm

त्रिभुज PQR को परिमिति (perimeter)=?

अब, P =PQ+QR+QR

=5.5cm+8.5cm+5cm

=19cm

Click if Answers are correct.

क) उत्तर,

यहा,त्रिभुज ABC को भुजा (AB )=12 cm

त्रिभुज ABC को भुजा (BC)=5 cm

त्रिभुज ABC को भुजा (AC )=13cm

त्रिभुज ABC को परिमिति (perimeter)=?

अब, P =AB+BC+AC

=12cm+5cm+13cm

=20cm

Click if Answers are correct.

ग) उत्तर,

यहा,त्रिभुज PQR को भुजा (PQ )=5.5 cm

त्रिभुज PQR को भुजा (QR)=8.5 cm

त्रिभुज PQR को भुजा (PR )=5cm

त्रिभुज PQR को परिमिति (perimeter)=?

अब, P =PQ+QR+QR

=5.5cm+8.5cm+5cm

=29cm

Create a free account and access millions of resources

Create resources

Host any resource

Get auto-graded reports

Continue with Google

Continue with Email

Continue with Classlink

Continue with Clever

or continue with

Microsoft

Apple

Others

Already have an account?

Similar Resources on Wayground

33 questions

Scale Factor for Similar Figures

Quiz

•

7th - 8th Grade

31 questions

Angles, droites, triangles et polygônes

Quiz

•

7th Grade

40 questions

Chapter 9 Test Review

Quiz

•

6th - 9th Grade

35 questions

Equations that will solve for tax discount and more

Quiz

•

6th - 8th Grade

32 questions

Repaso 2 divisibilidad, números enteros y potencias

Quiz

•

6th - 7th Grade

33 questions

Monomi. Darbības ar monomiem.

Quiz

•

7th Grade

33 questions

Ratios and Rates

Quiz

•

6th - 8th Grade

39 questions

Year 7 - Factors, multiples, LCF, HCM, prime numbers

Quiz

•

4th - 9th Grade

Popular Resources on Wayground

5 questions

This is not a...winter edition (Drawing game)

Quiz

•

1st - 5th Grade

15 questions

4:3 Model Multiplication of Decimals by Whole Numbers

Quiz

•

5th Grade

25 questions

Multiplication Facts

Quiz

•

5th Grade

10 questions

The Best Christmas Pageant Ever Chapters 1 & 2

Quiz

•

4th Grade

12 questions

Unit 4 Review Day

Quiz

•

3rd Grade

10 questions

Identify Iconic Christmas Movie Scenes

Interactive video

•

6th - 10th Grade

20 questions

Christmas Trivia

Quiz

•

6th - 8th Grade

18 questions

Kids Christmas Trivia

Quiz

•

KG - 5th Grade

Discover more resources for Mathematics

10 questions

Identify Iconic Christmas Movie Scenes

Interactive video

•

6th - 10th Grade

15 questions

Christmas Movie Trivia

Quiz

•

7th Grade

20 questions

One-Step Inequalities

Quiz

•

7th Grade

10 questions

Guess the Christmas Movie by the Scene Challenge

Interactive video

•

6th - 10th Grade

18 questions

Solve Integer Problems and Concepts

Quiz

•

7th Grade

20 questions

Solving One-Step Equations

Quiz

•

6th - 9th Grade

20 questions

Adding and Subtracting integers

Quiz

•

7th Grade

20 questions

Proportional Relationships in Tables, Graphs, and Equations

Quiz

•

7th Grade

class 7 math quiz

36 questions

घ) Solution:Interior<AOB+ exterior <AOB=360°or,80°+7y=360°or,7y=360°-80°or,7y=280°or,y=280°/7y=40°क) Solution:<AOB+<AOC=180°[° .° Being Supplementary angle's sum]or,2x+3x+45°=180°or,5x+45°=180°or,5x=180°-45°or,5x=135°or,x=135°/5x=27°

Find the value of x , y and a from given figure:(answer are given below click which are correct.)

See figure,Click if answer is correct.

Click if given below statement are correct .

If AB//CD, Find the value of x, y and z from given figure.click,which are correct answer?

Create a free account and access millions of resources

Similar Resources on Wayground

Popular Resources on Wayground

Discover more resources for Mathematics

घ) Solution:
Interior<AOB+ exterior <AOB=360°
or,80°+7y=360°
or,7y=360°-80°
or,7y=280°
or,y=280°/7
y=40°
क) Solution:
<AOB+<AOC=180°[° .° Being Supplementary angle's sum]
or,2x+3x+45°=180°
or,5x+45°=180°
or,5x=180°-45°
or,5x=135°
or,x=135°/5
x=27°

Find the value of x , y and a from given figure:
(answer are given below click which are correct.)

If AB//CD, Find the value of x, y and z from given figure.
click,which are correct answer?